以编程方式获取网关和子网掩码详细信息 [英] Programmatically getting the gateway and subnet mask details
问题描述
如何在 Android 中获取网关和子网掩码详细信息?
How can I get gateway and subnet mask details in Android?
推荐答案
我在 android.net
包中找到了一个名为 DhcpInfo
的类.它有一些公共变量,用于存储当前网络参数的值.但问题是他们返回的是从 8Bit 移位二进制转换而来的整数值.
I have found a class called DhcpInfo
within the android.net
package. It has some public variables that stores the values of current Network parameters. But the problem is they return the value in integer converted from 8Bit shifted binary.
描述场景的示例图像:
****这是一个示例代码:**
****Here is a sample code:**
**java 文件:****
**java file:****
package com.schogini.dhcp;
import android.app.Activity;
import android.content.Context;
import android.os.Bundle;
import android.widget.TextView;
import android.net.*;
import android.net.wifi.WifiManager;
public class dhcpInfo extends Activity {
public String s_dns1 ;
public String s_dns2;
public String s_gateway;
public String s_ipAddress;
public String s_leaseDuration;
public String s_netmask;
public String s_serverAddress;
TextView info;
DhcpInfo d;
WifiManager wifii;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
wifii= (WifiManager) getSystemService(Context.WIFI_SERVICE);
d=wifii.getDhcpInfo();
s_dns1="DNS 1: "+String.valueOf(d.dns1);
s_dns2="DNS 2: "+String.valueOf(d.dns2);
s_gateway="Default Gateway: "+String.valueOf(d.gateway);
s_ipAddress="IP Address: "+String.valueOf(d.ipAddress);
s_leaseDuration="Lease Time: "+String.valueOf(d.leaseDuration);
s_netmask="Subnet Mask: "+String.valueOf(d.netmask);
s_serverAddress="Server IP: "+String.valueOf(d.serverAddress);
//dispaly them
info= (TextView) findViewById(R.id.infolbl);
info.setText("Network Info
"+s_dns1+"
"+s_dns2+"
"+s_gateway+"
"+s_ipAddress+"
"+s_leaseDuration+"
"+s_netmask+"
"+s_serverAddress);
}
}
xml 编码:
<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.schogini.dhcp"
android:versionCode="1"
android:versionName="1.0">
<uses-sdk android:minSdkVersion="4" />
<application android:icon="@drawable/icon" android:label="@string/app_name">
<activity android:name=".dhcpInfo"
android:label="@string/app_name">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
</application>
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.ACCESS_WIFI_STATE" />
</manifest>
我尝试将整数值转换为其等效值,但我不能.如果你这样做,你可以回帖..再见..
I tried converting the integer value to its equivalent but i couldn't. If you do so you can post back.. Bye..
更新:一些如何设法将 IP 从整数形式转换为 v4 格式转换为 IPv4 格式:
UPDATE: Some how managed to convert the IP to v4 Format from the integer form Conversion to IPv4 Format:
public String intToIp(int i) {
return ((i >> 24 ) & 0xFF ) + "." +
((i >> 16 ) & 0xFF) + "." +
((i >> 8 ) & 0xFF) + "." +
( i & 0xFF) ;
}
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