JavaFX - setVisible 隐藏元素但不重新排列相邻节点 [英] JavaFX - setVisible hides the element but doesn't rearrange adjacent nodes
问题描述
在 JavaFX 中,如果我有一个包含 2 个 VBox
元素的场景,并且每个 VBox
中都有多个 Label
.
如果我将顶部VBox
设置为invisible,为什么底部VBox
不向上移动顶部的场景VBox
是 ?
In JavaFX, if I have a scene with 2 VBox
elements and each VBox
has multiple Label
in it.
If I set the top VBox
to invisible, why does the bottom VBox
not move up the scene where the top VBox
was ?
VBox
不可见,但我希望其他对象移动到它的位置.
The VBox
is invisible but I would expect the other objects to move into its place.
我正在使用 FXML 加载我的控件.
I am using FXML to load my controls.
推荐答案
Node.setVisible(boolean)
只是切换 Node
的可见性状态.
Node.setVisible(boolean)
just toggles the visibility state of a Node
.
要从其父布局计算中排除 Node
,您还必须通过调用 Node.setManaged(false)
.
To exclude a Node
from its parents layout calculations you additionally have to set its managed state, by calling Node.setManaged(false)
.
如果您希望托管状态与可见性一起自动更新,您可以使用@jewelsea 指出的绑定:node.managedProperty().bind(node.visibleProperty());
If you want the managed state to be updated automatically alongside the visibility, you can use a binding as @jewelsea pointed out: node.managedProperty().bind(node.visibleProperty());
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