在 Django 中编写一个非常基本的搜索表单 [英] Writing a very basic search form in Django

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问题描述

所以我试图完成一些非常简单的事情.我想在我的搜索框中输入一个术语,并将其显示在结果页面上.

我的表单 HTML 是

views.py 看起来像这样:

def 搜索(请求):查询 = request.GET['q']t = loader.get_template('模板/结果.html')c = 上下文({'查询':查询,})返回 HttpResponse(t.render(c))

最后的结果模板包含:

您搜索的是:{{ query }} </div>

这是 urls.py

urlpatterns = patterns('',url(r'^home/$', 'search.views.home'),url(r'^results/$', 'search.views.results'),

{{ query }} 空间中没有显示任何内容.

解决方案

好的所以在你的 views.py 中处理搜索的操作应该是 search 但作为我怀疑在你的 urls.py 中你没有在任何地方调用 search 方法.

你在哪里执行search方法?

网址应该是这样的:

urlpatterns = patterns('',url(r'^home/$', 'search.views.home'),url(r'^results/$', 'search.views.search'),# 或者至少有一个搜索视图的 url

注意表单中的 action 属性

它是 action="/results/".这意味着结果视图是应该处理表单的人.您也可以将其更改为 action="/search/" 并让您的网址如下所示:

urlpatterns = patterns('',url(r'^home/$', 'search.views.home'),url(r'^results/$', 'search.views.results'),url(r'^search/$', 'search.views.search'),

So I'm trying to get something very simple accomplished. I want to enter a term into my search box, and display it on the resulting page.

My HTML for the form is

<form method="get" action="/results/" class="navbar-form pull-right">
<input type="text" id="searchBox" class="input-medium search-query" name="q" placeholder="Search">
<input type="submit" class="btn" value="Search" >
</form>

The views.py looks like this:

def search(request):
    query = request.GET['q']
    t = loader.get_template('template/results.html')
    c = Context({ 'query': query,})
    return HttpResponse(t.render(c))

And finally the result template contains:

<div>You searched for: {{ query }} </div>

Here's the urls.py

urlpatterns = patterns('',
url(r'^home/$', 'search.views.home'),
url(r'^results/$', 'search.views.results'),

Nothing is showing up in the {{ query }} space.

解决方案

Ok so the action handling the search in your views.py is supposed to be search but as I suspected in your urls.py you don't call the search method anywhere.

Where do you execute search method?

Urls should be like this:

urlpatterns = patterns('',
url(r'^home/$', 'search.views.home'),
url(r'^results/$', 'search.views.search'),
# or at least have a url for the search view

Note the action attribute in your form

It is action="/results/". This means result view is the one who is supposed to be handling the form. You may also change this to action="/search/" and have your urls like this:

urlpatterns = patterns('',
url(r'^home/$', 'search.views.home'),
url(r'^results/$', 'search.views.results'),
url(r'^search/$', 'search.views.search'),

这篇关于在 Django 中编写一个非常基本的搜索表单的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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