void 函数中出现意外的非空返回值 - Swift 4(Firebase、Firestore) [英] Unexpected non-void return value in void function - Swift 4 (Firebase, Firestore)
问题描述
所以我想要一个布尔函数,它根据 users
集合中的用户是否存在给定的电子邮件来返回 true 或 false.
So I want a Boolean function that returns true or false depending on whether the given email exists for a user in the users
collection.
但是,如果我尝试在 getDocuments
调用中返回 True
或 False
,我会收到错误:non-void return value在 void 函数中
However if I try and return True
or False
within the getDocuments
call I get the error: non-void return value in void function
func checkUserWith(email: String) -> Bool
{
let usersDB = database.collection("users")
usersDB.whereField("email", isEqualTo: email).getDocuments { (snapshot, error) in
if error != nil
{
print("Error: (error?.localizedDescription ?? "")")
return false
}
for document in (snapshot?.documents)! {
if document.data()["email"]! as! String == email {
return true
}
}
return false
}
}
我有一种感觉,这是因为我试图在 Firestore 调用中返回一个布尔值,该布尔值需要不同的变量类型?
I have a feeling it is because I am trying to return a boolean within the Firestore call which is expecting a different variable type?
推荐答案
由于 firebase 操作给你一个回调闭包,而且调用是异步的,我相信你不可能直接从闭包返回.但是,您可以按如下方式返回一个指示 true 或 false 的转义闭包...
Since the firebase operation gives you a callback closure, and the calls made asynchronously, I believe it wont be possible for you to directly return from closures. However, you can return an escaping closure indicating true or false as follows...
func checkUserWith(email: String, completion: @escaping (Bool) -> Void)
{
let usersDB = database.collection("users")
usersDB.whereField("email", isEqualTo: email).getDocuments { (snapshot, error) in
if error != nil
{
print("Error: (error?.localizedDescription ?? "")")
completion(false)
}
for document in (snapshot?.documents)! {
if document.data()["email"]! as! String == email {
completion(true)
return
}
}
completion(false)
}
}
然后当你调用这个方法时:
Then when you call this method:
checkUserWith(email: emailHere) { (isSucceeded) in
if isSucceeded {
//it exists, do something
} else {
//user does not exist, do something else
}
}
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