无法让 Firestore 规则 get() 在函数内工作 [英] Can't get Firestore Rules get() to work inside a function
问题描述
Firestore 与函数内的 get 不能很好地结合
Firestore doesn't work well with get inside a function
我有这个规定
service cloud.firestore {
match /databases/{database}/documents {
function isProjectOpenForAssign() {
return get(/databases/$(database)/documents/projects/$(anyProject)).data.canAssignTask == true;
}
match /projects/{anyProject} {
allow create: if request.auth != null;
match /tasks/{anyTask} {
allow create: if request.auth != null && (isProjectOpenForAssign());
}
}
}
}
运行模拟器测试时,我得到:
When running the simulator testing it I get:
运行模拟时出错 — 错误:simulator.rules 行 [23],列 [14].找不到函数错误:名称:[get].;错误:提供给调用的参数无效.函数:[get],参数:["||invalid_argument||"]
Error running simulation — Error: simulator.rules line [23], column [14]. Function not found error: Name: [get].; Error: Invalid argument provided to call. Function: [get], Argument: ["||invalid_argument||"]
推荐答案
问题出在您定义函数的范围内.由于您将 isProjectOpenForAssign
定义在与此匹配 match/projects/{anyProject}
相同的级别,因此该函数将无法访问 anyProject
.
The problem is in the scope of where you define your function. Since you define isProjectOpenForAssign
at the same level as this match match /projects/{anyProject}
, the function won't have access to anyProject
.
有两种解决方案:
将
anyProject
作为参数传递给isProjectOpenForAssign
.
function isProjectOpenForAssign(anyProject) {
return get(/databases/$(database)/documents/projects/$(anyProject)).data.canAssignTask == true;
}
match /projects/{anyProject} {
allow create: if request.auth != null;
match /tasks/{anyTask} {
allow create: if request.auth != null && (isProjectOpenForAssign(anyProject));
}
}
在声明anyProject
的匹配中定义函数.
match /projects/{anyProject} {
function isProjectOpenForAssign() {
return get(/databases/$(database)/documents/projects/$(anyProject)).data.canAssignTask == true;
}
allow create: if request.auth != null;
match /tasks/{anyTask} {
allow create: if request.auth != null && (isProjectOpenForAssign());
}
}
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