如何在 Android 和 iOS 的 Xamarin 形式中实现 Deeplink(通用链接)? [英] How to Implement Deeplink(Universal Linking) In Xamarin forms Both Android and iOS?

问题描述

伙计们，我需要在 android 和 iOS 上逐步实现 Applink(通用链接)，请任何人帮助实现这一目标.我在我的 android 项目中尝试了以下代码

Guys, I need to implement Applink (Universal Link) step by step both android and iOS, please any to help achieve this. I tried the following code in my android project

我按照这个 URL 写了这个 https://devblogs.microsoft.com/xamarin/connect-with-your-users-with-google-search-and-app-indexing/

I followed this URL to write this https://devblogs.microsoft.com/xamarin/connect-with-your-users-with-google-search-and-app-indexing/

注意我不需要索引概念，只想通过单击任何 URL 来打开应用程序

Note I no need to indexing concept just want to open the app from Clicking of any URL

1. 首先我安装了 Xamarin.Forms.AppLinks NuGet

1. First I Installed Xamarin.Forms.AppLinks NuGet

下面的代码 MainActivity

Below code MainActivity

[IntentFilter(new[] { Android.Content.Intent.ActionView },
        Categories = new[]
        {
            Android.Content.Intent.CategoryDefault,
            Android.Content.Intent.CategoryBrowsable
        },
        DataScheme = "http",
        DataPathPrefix = "/",
        DataHost = "test.com")]

1. 然后在OnCreate方法中编写波纹管代码

  AndroidAppLinks.Init(this);

1. 然后我尝试从 Deep Link Tester 调用深层链接 URLtest://DeeplinkingSample"

它说没有找到处理意图的活动

Its saying No Activity found to handle the intent

推荐答案

4.然后我尝试调用深层链接网址test://DeeplinkingSample"；来自 Deep Link Tester

4.Then I try to call deeplink url "test://DeeplinkingSample" from Deep Link Tester

它说没有找到处理意图的活动

Its saying No Activity found to handle intent

您正在尝试调用 URL test://DeeplinkSample，其中包含以下部分

You are trying to call the URL test://DeeplinkSample, which has the following parts

• 方案是test
• 宿主是DeeplinkSample
• 没有数据路径

但是，您没有为该 URL 注册您的活动，而是为方案 http 注册了活动，使用主机 test.com 和数据路径前缀 /(即大概所有以 / 开头的数据路径).因此，当您尝试打开应用程序时应该会打开

However, you did not register your activity for that URL, but for the scheme http, with the host test.com and the data path prefix / (i.e. presumably all data paths that start with /). Hence the app should open when you are trying to open

http://test.com/...

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