如何检测我的任何活动是否位于最前面并且对用户可见? [英] How to detect if any of my activity is front-most and visible to user?

问题描述

我想在我的任何活动可见时启动一个意图，否则我会将其作为通知发布，并且会被用户触发.

I would like to launch an intent when any of my activity is visible, otherwise I will put it up as a notification, and will be fired by the user.

要确定这一点，我需要知道我的任何活动是否位于最前面，我该怎么做?

To decide this, I need to know if any of my activity is front-most, how do I that?

推荐答案

我不知道有没有一种方法可以获取当前显示的活动，但是您可以结合 Activity Lifecycle 和一个标志.

I don't know that there's a method to get the currently displayed activity, but you could do something combining the Activity Lifecycle and a flag.

对于标志，如果您扩展了 Application 类，这可能是一个不错的存储位置.为了扩展应用程序类，这个问题的最佳答案有信息.(d).

For the flag, if you've extended the Application class, that's probably a decent place to store it. For extending the application class, the top answer to this question has info. (d).

因此可能会根据您想要的行为在 onResume/onPause 或 onStart/onStop 中跟踪当前的活动活动(或活动可见的标志).

So probably keep track of the current active activity (or a flag that the activity is visible) in onResume/onPause or onStart/onStop depending on exactly what behavior you want.

由于您有多个活动，因此您需要一个质心位置来存储标志，这就是应用程序有意义的原因.您可以通过转换应用程序上下文来获取自定义 Application 对象(例如 ((MyApplication)getApplicationContext()).isMyActivityActive).

Since you have multiple activities, you'll need a centroid place for storing the flag, which is why the Application makes sense. You can get the custom Application object by casting the application context (e.g. ((MyApplication)getApplicationContext()).isMyActivityActive).

您也可以扩展 Activity 以帮助保持此代码的整洁和包含.

You could extend Activity as well to help keep this code clean and contained.

如果您正在使用服务，则可以在 onStart/onStop(或 onResume/onPause)中的每个活动中绑定到该服务.如果绑定，您就可见.

If you're using a service you could bind to the service in every activity in the onStart/onStop (or onResume/onPause). If bound, you're visible.

这篇关于如何检测我的任何活动是否位于最前面并且对用户可见?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！