ES6 从对象导出所有值 [英] ES6 export all values from object

问题描述

假设我有一个模块 (./my-module.js)，它有一个对象，它应该是它的返回值:

Say I have a module (./my-module.js) that has an object which should be its return value:

let values = { a: 1, b: 2, c: 3 }

// "export values" results in SyntaxError: Unexpected token

所以我可以像这样导入它们:

So I can import them like:

import {a} from './my-module'           // a === 1
import * as myModule from './my-module' // myModule.a === 1

我发现的唯一方法是对导出进行硬编码:

The only way I found is by hard coding the exports:

export let a = values.a
export let b = values.b
export let c = values.c
// or:
export let {a, b, c} = values

这不是动态的.

是否可以从对象中导出所有值?

Is it possible to export all values from an object?

推荐答案

似乎并非如此.引用自 ECMAScript 6 模块:最终语法:

Does not seem so. Quote from ECMAScript 6 modules: the final syntax:

您可能想知道 - 如果我们可以简单地默认导出对象(如 CommonJS)，为什么我们需要命名导出?答案是您不能通过对象强制执行静态结构并失去所有相关优势(在下一节中描述).

You may be wondering – why do we need named exports if we could simply default-export objects (like CommonJS)? The answer is that you can’t enforce a static structure via objects and lose all of the associated advantages (described in the next section).

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