如何使用 BeautifulSoup 从内联样式中提取 CSS 属性 [英] How to pull out CSS attributes from inline styles with BeautifulSoup
问题描述
我有这样的事情:
<img style="background:url(/theRealImage.jpg) no-repate 0 0; height:90px; width:92px;") src="notTheRealImage.jpg"/>我正在使用 beautifulsoup 来解析 html.是否可以在背景"css 属性中提取url"?
您有几个选择 - 快速和肮脏或正确的方式.快速而肮脏的方式(如果更改标记很容易破坏)看起来像
<预><代码>>>>从 BeautifulSoup 导入 BeautifulSoup>>>进口重新>>>汤 = BeautifulSoup('<html><body><img style="background:url(/theRealImage.jpg) no-repate 0 0; height:90px; width:92px;") src="notTheRealImage.jpg"/></body></html>')>>>样式 = 汤.find('img')['style']>>>urls = re.findall('url((.*?))', style)>>>网址[u'/theRealImage.jpg']显然，您必须使用它才能使其与多个 img 标签一起使用.
正确的方法，因为我觉得建议某人在 CSS 字符串上使用正则表达式很糟糕:)，使用 CSS 解析器.cssutils 是我刚刚在 Google 上找到并在 PyPi 上可用的一个库，看起来它可以完成这项工作.
I have something like this:
<img style="background:url(/theRealImage.jpg) no-repate 0 0; height:90px; width:92px;") src="notTheRealImage.jpg"/>
I am using beautifulsoup to parse the html. Is there away to pull out the "url" in the "background" css attribute?
You've got a couple options- quick and dirty or the Right Way. The quick and dirty way (which will break easily if the markup is changed) looks like
>>> from BeautifulSoup import BeautifulSoup
>>> import re
>>> soup = BeautifulSoup('<html><body><img style="background:url(/theRealImage.jpg) no-repate 0 0; height:90px; width:92px;") src="notTheRealImage.jpg"/></body></html>')
>>> style = soup.find('img')['style']
>>> urls = re.findall('url((.*?))', style)
>>> urls
[u'/theRealImage.jpg']
Obviously, you'll have to play with that to get it to work with multiple img tags.
The Right Way, since I'd feel awful suggesting someone use regex on a CSS string :), uses a CSS parser. cssutils, a library I just found on Google and available on PyPi, looks like it might do the job.
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