用 Beautiful Soup 提取 href [英] Extracting href with Beautiful Soup

问题描述

我使用此代码访问我的链接:

I use this code to get acces to my link :

links = soup.find("span", { "class" : "hsmall" })
links.findNextSiblings('a')
for link in links:
  print link['href']
  print link.string

链接没有 ID 或类或其他什么，它只是一个带有 href 属性的经典链接.

Link have no ID or class or whatever, it's just a classic link with a href attribute.

我的脚本的响应是:

print link['href']
TypeError: string indices must be integers

你能帮我获取 href 值吗?谢谢！

Can you help me to get href value ? Thx !

推荐答案

好的，现在可以使用以下代码:

Okay, it works now with following code :

linkSpan = soup.find("span", { "class" : "hsmall" })
link = [tag.attrMap['href'] for tag in linkSpan.findAll('a', {'href': True})]
for lien in link:
  print "LINK = " + lien`

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