使用 awk 打印除第一个字段之外的所有内容 [英] Printing everything except the first field with awk

问题描述

我有一个看起来像这样的文件:

I have a file that looks like this:

AE  United Arab Emirates
AG  Antigua & Barbuda
AN  Netherlands Antilles
AS  American Samoa
BA  Bosnia and Herzegovina
BF  Burkina Faso
BN  Brunei Darussalam

我想颠倒顺序，首先打印除 $1 之外的所有内容，然后打印 $1:

And I 'd like to invert the order, printing first everything except $1 and then $1:

United Arab Emirates AE

我怎样才能做到除了字段 1 之外的所有东西"?

How can I do the "everything except field 1" trick?

推荐答案

Assigning $1 有效，但会留下前导空格: awk '{first = $1;$1 = "";先打印 $0；}'

Assigning $1 works but it will leave a leading space: awk '{first = $1; $1 = ""; print $0, first; }'

您还可以在 NF 中找到列数并在循环中使用它.

You can also find the number of columns in NF and use that in a loop.

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