如何在查找表达式中使用带有 sed 的文件名 [英] How to use the name of the file with sed in a find expression

问题描述

尝试回答使用 Bash/Perl 根据每个文件的名称修改文件不知道如何一起使用 find 和 sed.

Trying to answer Using Bash/Perl to modify files based on each file's name I ended in a point in which I don't know how to use find and sed all together.

假设有一个特定的文件结构，我们要在其中更改一行，附加文件名.

Let's say there is a certain structure of files in which we want to change a line, appending the name of the file.

如果它是一个普通的 for 循环，我们会这样做:

If it was a normal for loop we would do:

for file in dir/*
do
   sed -i "s/text/text plus $file/g" $file
done

但是假设我们要使用 find 来更改所有子目录中的文件.在这种情况下，我会使用...

But let's say we want to use find to change files from all subdirectories. In this case, I would use...

find . -type f -exec sed -i "s/text/text plus {}/g" {} ;
                                              ^
                                   it does not like this part

但是sed 中的这些{} 不被接受，我收到错误

but these {} within sed are not accepted and I get the error

sed:-e 表达式 #1，字符 20:`s' 的未知选项

sed: -e expression #1, char 20: unknown option to `s'

我发现了一些类似的问题(1)但无法概括到足以让我在这种情况下可以理解.

I found some similar questions (1) but could not generalize it enough to make it understandable for me in this case.

我相信你们会为此提供一个很好的解决方案.谢谢！

I am sure you guys will come with a great solution for this. Thanks!

推荐答案

find 将根据您指定的路径返回 pathnames(相对或绝对).

find would return pathnames (relative or absolute) depending upon the path you specify.

这会与您指定的分隔符冲突，即 /.更改 sed 的分隔符，你应该很好:

This would conflict with the delimiter you've specified, i.e. /. Change the delimiter for sed and you should be good:

find . -type f -exec sed -i "s|text|text plus {}|g" {} ;

要从路径中删除前导 ./，您可以尝试:

For removing the leading ./ from the paths, you can try:

find . -type f -exec sh -c '$f={}; f=${f/.//}; sed -i "s|text|text plus ${f}|g" {}' ;

我确信可能存在更好的解决方案......

I'm certain that better solutions might exist ...

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