如何使用 Cypher 返回节点的所有属性? [英] How can I return all properties for a node using Cypher?

问题描述

我知道可以使用通配符 (*) 来返回 Cypher 查询中的所有引用，例如:

I understand it is possible to use the wildcard (*) symbol to return all references in a Cypher query, such as:

MATCH p:Product WHERE p.price='1950' RETURN *;

  ==> +----------------------------------------------------------------+
  ==> | p                                                              |
  ==> +----------------------------------------------------------------+
  ==> | Node[686]{title:"Giorgio Armani Briefcase",price:"1950",...    |
  ==> +----------------------------------------------------------------+

然而，结果是一行带有名为p"的单个节点列"，可以从中访问属性.但是，我希望结果集行"的属性名称为列".类似的东西:

However, the result is a row with a single node 'column' named "p", from which the properties can be accessed. However, I'd like the result-set 'rows' to have the property names as 'columns'. Something like:

MATCH p:Product WHERE p.price='1950' RETURN p.*;

  ==> +-------------------------------------------+
  ==> | title | price | ...                       |
  ==> +-------------------------------------------+
  ==> | "Giorgio Armani Briefcase" | "1950" | ... |
  ==> +-------------------------------------------+

该特定查询无效，但有没有办法实现相同的结果(没有明确列出所有属性，如 p.title,p.price,p... )?

That particular query isn't valid, but is there a way to achieve the same result (short of listing all the properties explicitly, as in p.title,p.price,p... )?

推荐答案

您还不能在 Cypher 中执行此操作.我认为这将是一个不错的功能，如果你想请求它.

编辑(感谢评论指出):您现在可以从 2.2 开始执行此操作:

Edit (thanks for comment pointing it out): You can now do this as of 2.2:

MATCH (p:Product) WHERE p.price='1950' RETURN keys(p);

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