一般而言,boost bind 是如何在幕后工作的? [英] How does boost bind work behind the scenes in general?

查看:24
本文介绍了一般而言,boost bind 是如何在幕后工作的?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

无需花很长时间查看 boost 源代码,有人可以简要介绍一下 boost 绑定是如何实现的吗?

Without spending a long time reviewing the boost source code, could someone give me a quick rundown of how boost bind is implemented?

推荐答案

我喜欢这段 bind 源码:

template<class R, class F, class L> class bind_t
{
public:

    typedef bind_t this_type;

    bind_t(F f, L const & l): f_(f), l_(l) {}

#define BOOST_BIND_RETURN return
#include <boost/bind/bind_template.hpp>
#undef BOOST_BIND_RETURN

};

告诉你几乎所有你需要知道的,真的.

Tells you almost all you need to know, really.

bind_template 标头扩展为内联 operator() 定义列表.比如最简单的:

The bind_template header expands to a list of inline operator() definitions. For example, the simplest:

result_type operator()()
{
    list0 a;
    BOOST_BIND_RETURN l_(type<result_type>(), f_, a, 0);
}

我们可以看到 BOOST_BIND_RETURN 宏此时扩展为 return,所以该行更像是 return l_(type...).

We can see the BOOST_BIND_RETURN macro expands to return at this point so the line is more like return l_(type...).

一个参数版本在这里:

template<class A1> result_type operator()(A1 & a1)
{
    list1<A1 &> a(a1);
    BOOST_BIND_RETURN l_(type<result_type>(), f_, a, 0);
}

非常相似.

listN 类是参数列表的包装器.这里有很多深奥的魔法,但我并不太了解.他们还重载了调用神秘的 unwrap 函数的 operator().忽略一些编译器特定的重载,它不会做很多事情:

The listN classes are wrappers for the parameter lists. There is a lot of deep magic going on here that I don't really understand too much though. They have also overloaded operator() that calls the mysterious unwrap function. Ignoring some compiler specific overloads, it doesn't do a lot:

// unwrap

template<class F> inline F & unwrap(F * f, long)
{
    return *f;
}

template<class F> inline F & unwrap(reference_wrapper<F> * f, int)
{
    return f->get();
}

template<class F> inline F & unwrap(reference_wrapper<F> const * f, int)
{
    return f->get();
}

命名约定似乎是:Fbind 的函数参数的类型.R 是返回类型.L 往往是一个参数类型列表.还有很多复杂性,因为不同数量的参数有不少于九个重载.最好不要想太多.

The naming convention seems to be: F is the type of the function parameter to bind. R is the return type. L tends to be a list of parameter types. There are also a lot of complications because there are no less than nine overloads for different numbers of parameters. Best not to dwell on that too much.

这篇关于一般而言,boost bind 是如何在幕后工作的?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆