new mysqli():如何拦截“无法连接"错误? [英] new mysqli(): how to intercept an 'unable to connect' error?

问题描述

我正在这样做(是的，我使用了错误的连接数据，这是为了强制连接错误)

try {
    $connection = new mysqli('localhost', 'my_user', 'my_password', 'my_db') ;
} catch (Exception $e ) {
    echo "Service unavailable";
    exit (3);
}

但是 PHP 正在这样做 php_warning:

But PHP is doing this php_warning:

mysqli::mysqli(): (28000/1045): 用户 'my_user'@'localhost' 访问被拒绝(使用密码:YES)

mysqli::mysqli(): (28000/1045): Access denied for user 'my_user'@'localhost' (using password: YES)

在示例中，我使用错误的连接数据来强制连接错误，但在现实世界中，数据库可能已关闭，或者网络可能已关闭......等等.

In the example I'm using wrong connection data to force a connection error, but in the real world the database could be down, or the network could be down... etc..

问题:有没有办法在不抑制警告的情况下拦截数据库连接问题?

Question: Is there a way, without suppressing warnings, to intercept a problem with the database connection ?

推荐答案

你需要告诉mysqli抛出异常:

You need to tell mysqli to throw exceptions:

mysqli_report(MYSQLI_REPORT_STRICT);

try {
     $connection = new mysqli('localhost', 'my_user', 'my_password', 'my_db') ;
} catch (Exception $e ) {
     echo "Service unavailable";
     echo "message: " . $e->message;   // not in live code obviously...
     exit;
}

现在您将捕获异常并从那里获取它.

Now you will catch the exception and you can take it from there.

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