如何销毁 Sencha Touch 中的非活动视图 [英] How to destroy an inactive view in Sencha Touch

问题描述

我遇到了一个我认为非常重要的问题.在一个简单的 Sencha Touch 应用程序中，我有很多视图.我的 Mainview 是一个 TabPanel，底部带有停靠图标.有时在我的应用程序中，我会切换到 Tabpanel 之外的另一个视图.我不希望 DOM 因视图而过载，我不再需要了，所以我正在寻找一种解决方案来在视图处于非活动状态时销毁它.我试过这个，同时切换到我的控制器中的另一个视图:

i stuck with a problem which is really important i guess. In a simple Sencha Touch App I have many views. My Mainview is a TabPanel with docking icons in the bottom. Sometimes in my App I switch to another views which are outside of the Tabpanel. I don't want the DOM to overload with views, i don't need anymore so i'm searching for a solution to destroy a view, when its inactive. I've tried this, while switching into another view in my controller:

this.getMainview().destroy();

主视图似乎被删除了，但我收到一个错误:

It seems that the Mainview gets deleted but I get an error:

Uncaught TypeError: Cannot read property 'dom' of null

所以我猜 .destroy() - 方法有问题，还是有更好的方法来处理这个问题?

So i guess something's wrong with the .destroy() - Method or is there a better way to handle this problem?

推荐答案

在移动到新视图之前，您可以调用以下代码删除当前视图

Before moving to new view you can call bellow code to remove current view

Ext.Viewport.remove(Ext.Viewport.getActiveItem(), true);  

或者你也可以提供 item 对象代替 ActiveItem

or you can also provide item object instead ActiveItem

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