Android 应用程序 - 添加“共享"按钮在社交网络上分享应用程序 [英] Android app - Adding a "share" button to share the app on social networks

问题描述

我有一个应用，我想给它添加一个分享按钮.单击按钮后，我希望它打开以下窗口:

I have an app, and I'd like to add a share button to it. Once the button is clicked, I'd like it to open the following window:

然后用户将选择共享它的位置，它将显示以下默认消息:刚刚找到这个很棒的应用程序！在这里找到它:https://play.google.com/store/apps/details?id=com.ideashower.readitlater.pro"

Then the user will choose where to share it and it will display the following default message: "Just found this great app! Find it here:https://play.google.com/store/apps/details?id=com.ideashower.readitlater.pro"

你能告诉我怎么做吗?

推荐答案

方案一:启动ACTION_SEND Intent

在启动 SEND Intent 时，您通常应该将它包装在一个选择器中(通过 createChooser(Intent, CharSequence))，它将为用户提供适当的界面来选择如何发送您的数据，并允许您指定一个提示，指示它们是什么

Solution 1: Launch ACTION_SEND Intent

When launching a SEND intent, you should usually wrap it in a chooser (through createChooser(Intent, CharSequence)), which will give the proper interface for the user to pick how to send your data and allow you to specify a prompt indicating what they are doing.

Intent intent = new Intent();
intent.setAction(Intent.ACTION_SEND);

# change the type of data you need to share, 
# for image use "image/*"
intent.setType("text/plain");
intent.putExtra(Intent.EXTRA_TEXT, URL_TO_SHARE);
startActivity(Intent.createChooser(intent, "Share"));

解决方案 2:使用 ShareActionProvider

如果您只是想在溢出菜单中添加共享按钮，还可以查看 ShareActionProvider.

public boolean onCreateOptionsMenu(Menu menu) {
    getMenuInflater().inflate(R.menu.share, menu);
    MenuItem item = menu.findItem(R.id.share_item);
    actionProvider = (ShareActionProvider) item.getActionProvider();

    // Create the share Intent
    String shareText = URL_TO_SHARE;
    Intent shareIntent = ShareCompat.IntentBuilder.from(this)
        .setType("text/plain").setText(shareText).getIntent();
    actionProvider.setShareIntent(shareIntent);
    return true;
}

希望这会有所帮助.:)

Hope this helps. :)

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