MVC 3 - Ajax.BeginForm做一个完整的回发 [英] MVC 3 - Ajax.BeginForm does a full post back
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问题描述
在以下code,我使用Ajax.BeginForm到数据不同步后的行动。该行动被调用,但结果都显示为一个新的网页。我心中已经看了一吨的例子。这似乎并不难。我做了榜样概念(POC)的证明非常简单,但我仍然看到显示了新的一页。
控制器
[HttpPost]
[的OutputCache(位置= OutputCacheLocation.None,NoStore = TRUE)]
公共字符串TestAjax(UserViewModel视图模型)
{ 返回viewModel.UserName;
}
查看
@model BasicMvc3Example2.Models.UserViewModel@ {
ViewBag.Title =索引2;
布局= NULL; //〜/查看/共享/ _Layout.cshtml
} <脚本的src =/ BasicMvc3Example2 /脚本/ jQuery的-1.4.4.js类型=文/ JavaScript的>< / SCRIPT>
<脚本的src =/ BasicMvc3Example2 /脚本/ jQuery的-ui.js类型=文/ JavaScript的>< / SCRIPT>
<脚本的src =/ BasicMvc3Example2 /脚本/ jquery.validate.js类型=文/ JavaScript的>< / SCRIPT>
<脚本的src =/ BasicMvc3Example2 /脚本/ jquery.validate.unobtrusive.js类型=文/ JavaScript的>< / SCRIPT>
< H2>索引2< / H> <脚本类型=文/ JavaScript的>
功能PostFailure(){
警报(失败);
} 功能PostSuccess(){
警报(成功);
} 功能PostOnComplete(){
警报(完整);
}
< / SCRIPT> 页面渲染:@ DateTime.Now.ToLongTimeString()
@using(Ajax.BeginForm(TestAjax,新AjaxOptions {列举HTTPMethod =邮报,UpdateTargetId =textEntered,onFailure处=PostFailure的onSuccess =PostSuccess的onComplete =PostOnComplete}))
{
< DIV>
@ Html.LabelFor(M = GT; m.UserName)
@ Html.TextBoxFor(M = GT; m.UserName)
< / DIV> < DIV>
@ Html.LabelFor(M = GT; m.Password)
@ Html.TextBoxFor(M = GT; m.Password)
< / DIV> < DIV>
@ Html.LabelFor(M = GT; m.EmailAddress)
@ Html.TextBoxFor(M = GT; m.EmailAddress)
< / DIV> <输入类型=提交ID =submitFormVALUE =提交表单/>
} < DIV ID =textEntered> D< / DIV>
解决方案
您可以检查 _Layout.cshtml
,并确保AJAX脚本引用?我不认为这是默认为:
<脚本的src =@ Url.Content(〜/脚本/ jquery.unobtrusive-ajax.min.js)TYPE =文/ JavaScript的>&LT ; / SCRIPT>
In the following code, I'm using Ajax.BeginForm to post data to the action asynchronously. The action gets called but the results are displayed to a new web page. I'v looked at a ton of example. This doesn't seem difficult. I've made the example extremely simple for a proof of concept (poc), but I'm still seeing a new page displayed.
Controller
[HttpPost]
[OutputCache(Location = OutputCacheLocation.None, NoStore = true)]
public string TestAjax(UserViewModel viewModel)
{
return viewModel.UserName;
}
View
@model BasicMvc3Example2.Models.UserViewModel
@{
ViewBag.Title = "Index2";
Layout = null;//"~/Views/Shared/_Layout.cshtml";
}
<script src="/BasicMvc3Example2/Scripts/jquery-1.4.4.js" type="text/javascript"></script>
<script src="/BasicMvc3Example2/Scripts/jquery-ui.js" type="text/javascript"></script>
<script src="/BasicMvc3Example2/Scripts/jquery.validate.js" type="text/javascript"></script>
<script src="/BasicMvc3Example2/Scripts/jquery.validate.unobtrusive.js" type="text/javascript"></script>
<h2>Index2</h2>
<script type="text/javascript">
function PostFailure(){
alert("Failure");
}
function PostSuccess(){
alert("Success");
}
function PostOnComplete() {
alert("Complete");
}
</script>
Page Rendered: @DateTime.Now.ToLongTimeString()
@using (Ajax.BeginForm("TestAjax", new AjaxOptions { HttpMethod = "Post", UpdateTargetId = "textEntered", OnFailure = "PostFailure", OnSuccess = "PostSuccess", OnComplete = "PostOnComplete" }))
{
<div>
@Html.LabelFor(m => m.UserName)
@Html.TextBoxFor(m => m.UserName)
</div>
<div>
@Html.LabelFor(m => m.Password)
@Html.TextBoxFor(m => m.Password)
</div>
<div>
@Html.LabelFor(m => m.EmailAddress)
@Html.TextBoxFor(m => m.EmailAddress)
</div>
<input type="submit" id="submitForm" value="Submit Form" />
}
<div id="textEntered">d</div>
解决方案
Can you check _Layout.cshtml
and make sure the ajax script is referenced? I don't think it is by default:
<script src="@Url.Content("~/Scripts/jquery.unobtrusive-ajax.min.js")" type="text/javascript"></script>
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