以字符串形式获取属性名称 [英] Get name of property as a string

问题描述

(请参阅下面我使用我接受的答案创建的解决方案)

(See below solution I created using the answer I accepted)

我正在尝试提高一些涉及反射的代码的可维护性.该应用程序有一个 .NET Remoting 接口，它公开(除其他外)一个名为 Execute 的方法，用于访问未包含在其发布的远程接口中的应用程序部分.

I'm trying to improve the maintainability of some code involving reflection. The app has a .NET Remoting interface exposing (among other things) a method called Execute for accessing parts of the app not included in its published remote interface.

以下是应用程序如何指定可通过执行访问的属性(本例中为静态属性):

Here is how the app designates properties (a static one in this example) which are meant to be accessible via Execute:

RemoteMgr.ExposeProperty("SomeSecret", typeof(SomeClass), "SomeProperty");

所以远程用户可以调用:

So a remote user could call:

string response = remoteObject.Execute("SomeSecret");

并且应用程序将使用反射来查找 SomeClass.SomeProperty 并将其值作为字符串返回.

and the app would use reflection to find SomeClass.SomeProperty and return its value as a string.

不幸的是，如果有人重命名 SomeProperty 并忘记更改 ExposeProperty() 的第三个参数，则会破坏此机制.

Unfortunately, if someone renames SomeProperty and forgets to change the 3rd parm of ExposeProperty(), it breaks this mechanism.

我需要相当于:

SomeClass.SomeProperty.GetTheNameOfThisPropertyAsAString()

用作 ExposeProperty 中的第三个参数，以便重构工具负责重命名.

to use as the 3rd parm in ExposeProperty so refactoring tools would take care of renames.

有没有办法做到这一点?

Is there a way to do this?

好的，这是我最终创建的内容(基于我选择的答案和他引用的问题):

Okay, here's what I ended up creating (based upon the answer I selected and the question he referenced):

// <summary>
// Get the name of a static or instance property from a property access lambda.
// </summary>
// <typeparam name="T">Type of the property</typeparam>
// <param name="propertyLambda">lambda expression of the form: '() => Class.Property' or '() => object.Property'</param>
// <returns>The name of the property</returns>
public string GetPropertyName<T>(Expression<Func<T>> propertyLambda)
{
    var me = propertyLambda.Body as MemberExpression;

    if (me == null)
    {
        throw new ArgumentException("You must pass a lambda of the form: '() => Class.Property' or '() => object.Property'");
    }

    return me.Member.Name;
 }

用法:

// Static Property
string name = GetPropertyName(() => SomeClass.SomeProperty);

// Instance Property
string name = GetPropertyName(() => someObject.SomeProperty);

现在有了这个很酷的功能，是时候简化 ExposeProperty 方法了.抛光门把手是一项危险的工作...

Now with this cool capability, it's time to simplify the ExposeProperty method. Polishing doorknobs is dangerous work...

推荐答案

从这里使用 GetMemberInfo:从 lambda 表达式中检索属性名称 你可以这样做:

Using GetMemberInfo from here: Retrieving Property name from lambda expression you can do something like this:

RemoteMgr.ExposeProperty(() => SomeClass.SomeProperty)

public class SomeClass
{
    public static string SomeProperty
    {
        get { return "Foo"; }
    }
}

public class RemoteMgr
{
    public static void ExposeProperty<T>(Expression<Func<T>> property)
    {
        var expression = GetMemberInfo(property);
        string path = string.Concat(expression.Member.DeclaringType.FullName,
            ".", expression.Member.Name);
        // Do ExposeProperty work here...
    }
}

public class Program
{
    public static void Main()
    {
        RemoteMgr.ExposeProperty("SomeSecret", () => SomeClass.SomeProperty);
    }
}

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