JAX-WS 客户端:访问本地 WSDL 的正确路径是什么? [英] JAX-WS client : what's the correct path to access the local WSDL?

查看：24 发布时间：2021/12/26 14:45:08 java netbeans client jax-ws

本文介绍了JAX-WS 客户端:访问本地 WSDL 的正确路径是什么?的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！

问题描述

问题是我需要从提供给我的文件构建一个 Web 服务客户端.我已将此文件存储在本地文件系统上，虽然我将 WSDL 文件保存在正确的文件系统文件夹中，但一切正常.当我将它部署到服务器或从文件系统文件夹中删除 WSDL 时，代理找不到 WSDL 并引发错误.我在网上搜索并找到了以下帖子，但我无法使其正常工作:
JAX-WS 从 jar 加载 WSDL
http://www.java.net/forum/topic/glassfish/metro-and-jaxb/client-jar-cant-find-local-wsdl-0
http://blog.vinodsingh.com/2008/12/locally-packaged-wsdl.html

我使用的是 NetBeans 6.1(这是一个遗留应用程序，我必须使用这个新的 Web 服务客户端进行更新).下面是 JAX-WS 代理类:

 @WebServiceClient(name = "SOAService", targetNamespace = "http://soaservice.eci.ibm.com/", wsdlLocation = "file:/C:/local/path/to/wsdl/SOAService.wsdl")公共类 SOAService扩展服务{私有最终静态 URL SOASERVICE_WSDL_LOCATION；私有最终静态记录器记录器 = Logger.getLogger(com.ibm.eci.soaservice.SOAService.class.getName());静止的 {URL url = null;尝试 {URL baseUrl;baseUrl = com.ibm.eci.soaservice.SOAService.class.getResource(".");url = new URL(baseUrl, "file:/C:/local/path/to/wsdl/SOAService.wsdl");} catch (MalformedURLException e) {logger.warning("未能为 wsdl 位置创建 URL:'file:/C:/local/path/to/wsdl/SOAService.wsdl'，作为本地文件重试");logger.warning(e.getMessage());}SOASERVICE_WSDL_LOCATION = url;}公共 SOAService(URL wsdlLocation, QName serviceName) {超级(wsdlLocation，服务名称)；}公共 SOAService() {super(SOASERVICE_WSDL_LOCATION, new QName("http://soaservice.eci.ibm.com/", "SOAService"));}/*** @返回* 返回 SOAServiceSoap*/@WebEndpoint(name = "SOAServiceSOAP")公共 SOAServiceSoap getSOAServiceSOAP() {return super.getPort(new QName("http://soaservice.eci.ibm.com/", "SOAServiceSOAP"), SOAServiceSoap.class);}/*** @param 功能* 要在代理上配置的 {@link javax.xml.ws.WebServiceFeature} 列表.支持的功能不在 <code>features</code> 中参数将具有它们的默认值.* @返回* 返回 SOAServiceSoap*/@WebEndpoint(name = "SOAServiceSOAP")公共 SOAServiceSoap getSOAServiceSOAP(WebServiceFeature... features) {return super.getPort(new QName("http://soaservice.eci.ibm.com/", "SOAServiceSOAP"), SOAServiceSoap.class, features);}}

这是我使用代理的代码:

 WebServiceClient annotation = SOAService.class.getAnnotation(WebServiceClient.class);//尝试复制代理设置URL baseUrl = com.ibm.eci.soaservice.SOAService.class.getResource("");//注意:代理使用."URL url = new URL(baseUrl, "/WEB-INF/wsdl/client/SOAService.wsdl");//URL wsdlUrl = this.getClass().getResource("/META-INF/wsdl/SOAService.wsdl");SOAService serviceObj = new SOAService(url, new QName(annotation.targetNamespace(), annotation.name()));代理 = serviceObj.getSOAServiceSOAP();/* 基地址；//classescomibmecisoaservice//URL url = new URL(baseUrl, "../../../../wsdl/SOAService.wsdl");proxy = new SOAService().getSOAServiceSOAP();*///更新服务端点映射<字符串，对象>ctxt = ((BindingProvider)proxy ).getRequestContext();ctxt.put(JAXWSProperties.HTTP_CLIENT_STREAMING_CHUNK_SIZE, 8192);ctxt.put(BindingProvider.ENDPOINT_ADDRESS_PROPERTY, WebServiceUrl);

NetBeans 将 WSDL 的副本放在 web-inf/wsdl/client/SOAService 中，所以我也不想将它添加到 META-INF.服务类位于 WEB-INF/classes/com/ibm/eci/soaservice/ 中，baseurl 变量包含文件系统的完整路径(c:path o heproject...服务).上面的代码引发了错误:

<块引用>

javax.xml.ws.WebServiceException:无法访问 WSDL:文件:/WEB-INF/wsdl/client/SOAService.wsdl.它失败了:WEB-INFwsdlclientSOAService.wsdl(找不到路径)

那么，首先要不要更新代理类的wsdllocation?那么如何告诉WEB-INF/classes/com/ibm/eci/soaservice中的SOAService类去搜索WEB-INFwsdlclientSOAService.wsdl中的WSDL?

已编辑:我找到了另一个链接 - http://jianmingli.com/wp/?cat=41，其中说将 WSDL 放入类路径.不好意思问:怎么放到web应用类路径中?

解决方案

最好的选择是使用 jax-ws-catalog.xml

当您编译本地 WSDL 文件时，覆盖 WSDL 位置并将其设置为类似

<前>http://localhost/wsdl/SOAService.wsdl

别担心，这只是一个 URI 而不是 URL，这意味着您不必在该地址获得 WSDL.
您可以通过将 wsdllocation 选项传递给 wsdl to java 编译器来实现这一点.

这样做会改变您的代理代码

静态{URL url = null;尝试 {URL baseUrl;baseUrl = com.ibm.eci.soaservice.SOAService.class.getResource(".");url = new URL(baseUrl, "file:/C:/local/path/to/wsdl/SOAService.wsdl");} catch (MalformedURLException e) {logger.warning("未能为 wsdl 位置创建 URL:'file:/C:/local/path/to/wsdl/SOAService.wsdl'，作为本地文件重试");logger.warning(e.getMessage());}SOASERVICE_WSDL_LOCATION = url;}

到

静态{URL url = null;尝试 {URL baseUrl;baseUrl = com.ibm.eci.soaservice.SOAService.class.getResource(".");url = 新 URL(baseUrl, "http://localhost/wsdl/SOAService.wsdl");} catch (MalformedURLException e) {logger.warning("未能为 wsdl 位置创建 URL:'http://localhost/wsdl/SOAService.wsdl'，作为本地文件重试");logger.warning(e.getMessage());}SOASERVICE_WSDL_LOCATION = url;}

注意在 URL 构造函数中 file://更改为 http://.

现在进入 jax-ws-catalog.xml.如果没有 jax-ws-catalog.xml，jax-ws 确实会尝试从

http://localhost/wsdl/SOAService.wsdl

并失败，因为没有这样的 WSDL 可用.

但是使用 jax-ws-catalog.xml，您可以在 jax-ws 尝试访问 WSDL 时将其重定向到本地打包的 WSDL @

http://localhost/wsdl/SOAService.wsdl

这里是 jax-ws-catalog.xml

<system systemId="http://localhost/wsdl/SOAService.wsdl"uri="wsdl/SOAService.wsdl"/></目录>

您正在做的是告诉 jax-ws，它何时需要从

http://localhost/wsdl/SOAService.wsdl

，它应该从本地路径 wsdl/SOAService.wsdl 加载它.

现在应该把 wsdl/SOAService.wsdl 和 jax-ws-catalog.xml 放在哪里?这不是百万美元的问题吗?
它应该在您的应用程序 jar 的 META-INF 目录中.

像这样

<前>ABCD文件|__ 元信息|__ jax-ws-catalog.xml|__ wsdl|__ SOAService.wsdl

这样您甚至不必覆盖访问代理的客户端中的 URL.WSDL 是从您的 JAR 中提取的，您不必在代码中使用硬编码的文件系统路径.

有关 jax-ws-catalog.xml 的更多信息http://jax-ws.java.net/nonav/2.1.2m1/docs/catalog-support.html

希望有帮助

The problem is I need to build a web service client from a file I'm been provided. I've stored this file on the local file system and, while I keep the WSDL file in the correct file system folder, everything is fine. When I deploy it to a server or remove the WSDL from the file system folder the proxy can't find the WSDL and rises an error. I've searched the web and I've found the following posts yet I'm not been able to make it work:
JAX-WS Loading WSDL from jar
http://www.java.net/forum/topic/glassfish/metro-and-jaxb/client-jar-cant-find-local-wsdl-0
http://blog.vinodsingh.com/2008/12/locally-packaged-wsdl.html

I'm using NetBeans 6.1 (this is a legacy application I've to update with this new web service client). Below is the JAX-WS proxy class :

    @WebServiceClient(name = "SOAService", targetNamespace = "http://soaservice.eci.ibm.com/", wsdlLocation = "file:/C:/local/path/to/wsdl/SOAService.wsdl")
public class SOAService
    extends Service
{

    private final static URL SOASERVICE_WSDL_LOCATION;
    private final static Logger logger = Logger.getLogger(com.ibm.eci.soaservice.SOAService.class.getName());

    static {
        URL url = null;
        try {
            URL baseUrl;
            baseUrl = com.ibm.eci.soaservice.SOAService.class.getResource(".");
            url = new URL(baseUrl, "file:/C:/local/path/to/wsdl/SOAService.wsdl");
        } catch (MalformedURLException e) {
            logger.warning("Failed to create URL for the wsdl Location: 'file:/C:/local/path/to/wsdl/SOAService.wsdl', retrying as a local file");
            logger.warning(e.getMessage());
        }
        SOASERVICE_WSDL_LOCATION = url;
    }

    public SOAService(URL wsdlLocation, QName serviceName) {
        super(wsdlLocation, serviceName);
    }

    public SOAService() {
        super(SOASERVICE_WSDL_LOCATION, new QName("http://soaservice.eci.ibm.com/", "SOAService"));
    }

    /**
     * @return
     *     returns SOAServiceSoap
     */
    @WebEndpoint(name = "SOAServiceSOAP")
    public SOAServiceSoap getSOAServiceSOAP() {
        return super.getPort(new QName("http://soaservice.eci.ibm.com/", "SOAServiceSOAP"), SOAServiceSoap.class);
    }

    /**
     * @param features
     *     A list of {@link javax.xml.ws.WebServiceFeature} to configure on the proxy.  Supported features not in the <code>features</code> parameter will have their default values.
     * @return
     *     returns SOAServiceSoap
     */
    @WebEndpoint(name = "SOAServiceSOAP")
    public SOAServiceSoap getSOAServiceSOAP(WebServiceFeature... features) {
        return super.getPort(new QName("http://soaservice.eci.ibm.com/", "SOAServiceSOAP"), SOAServiceSoap.class, features);
    }

}

This is my code to use the proxy :

   WebServiceClient annotation = SOAService.class.getAnnotation(WebServiceClient.class);
   // trying to replicate proxy settings
   URL baseUrl = com.ibm.eci.soaservice.SOAService.class.getResource("");//note : proxy uses "."
   URL url = new URL(baseUrl, "/WEB-INF/wsdl/client/SOAService.wsdl");
   //URL wsdlUrl = this.getClass().getResource("/META-INF/wsdl/SOAService.wsdl"); 
   SOAService serviceObj = new SOAService(url, new QName(annotation.targetNamespace(), annotation.name()));
   proxy = serviceObj.getSOAServiceSOAP();
   /* baseUrl;

   //classescomibmecisoaservice
   //URL url = new URL(baseUrl, "../../../../wsdl/SOAService.wsdl");

   proxy = new SOAService().getSOAServiceSOAP();*/
   //updating service endpoint 
   Map<String, Object> ctxt = ((BindingProvider)proxy ).getRequestContext();
   ctxt.put(JAXWSProperties.HTTP_CLIENT_STREAMING_CHUNK_SIZE, 8192);
   ctxt.put(BindingProvider.ENDPOINT_ADDRESS_PROPERTY, WebServiceUrl);

NetBeans put a copy of the WSDL in web-inf/wsdl/client/SOAService, so I don't want to add it to META-INF too. Service classes are in WEB-INF/classes/com/ibm/eci/soaservice/ and baseurl variable contains the filesystem full path to it (c:path o heproject...soaservice ). The above code raises the error:

javax.xml.ws.WebServiceException: Failed to access the WSDL at: file:/WEB-INF/wsdl/client/SOAService.wsdl. It failed with: WEB-INFwsdlclientSOAService.wsdl (cannot find the path)

So, first of all, shall I update the wsdllocation of the proxy class? Then how do I tell the SOAService class in WEB-INF/classes/com/ibm/eci/soaservice to search for the WSDL in WEB-INFwsdlclientSOAService.wsdl?

EDITED: I've found this other link - http://jianmingli.com/wp/?cat=41, which say to put the WSDL into the classpath. I'm ashamed to ask: how do I put it into the web application classpath?

解决方案

The best option is to use jax-ws-catalog.xml

When you compile the local WSDL file , override the WSDL location and set it to something like

http://localhost/wsdl/SOAService.wsdl

Don't worry this is only a URI and not a URL , meaning you don't have to have the WSDL available at that address.
You can do this by passing the wsdllocation option to the wsdl to java compiler.

Doing so will change your proxy code from

static {
    URL url = null;
    try {
        URL baseUrl;
        baseUrl = com.ibm.eci.soaservice.SOAService.class.getResource(".");
        url = new URL(baseUrl, "file:/C:/local/path/to/wsdl/SOAService.wsdl");
    } catch (MalformedURLException e) {
        logger.warning("Failed to create URL for the wsdl Location: 'file:/C:/local/path/to/wsdl/SOAService.wsdl', retrying as a local file");
        logger.warning(e.getMessage());
    }
    SOASERVICE_WSDL_LOCATION = url;
}

static {
    URL url = null;
    try {
        URL baseUrl;
        baseUrl = com.ibm.eci.soaservice.SOAService.class.getResource(".");
        url = new URL(baseUrl, "http://localhost/wsdl/SOAService.wsdl");
    } catch (MalformedURLException e) {
        logger.warning("Failed to create URL for the wsdl Location: 'http://localhost/wsdl/SOAService.wsdl', retrying as a local file");
        logger.warning(e.getMessage());
    }
    SOASERVICE_WSDL_LOCATION = url;
}

Notice file:// changed to http:// in the URL constructor.

Now comes in jax-ws-catalog.xml. Without jax-ws-catalog.xml jax-ws will indeed try to load the WSDL from the location

http://localhost/wsdl/SOAService.wsdl

and fail, as no such WSDL will be available.

But with jax-ws-catalog.xml you can redirect jax-ws to a locally packaged WSDL whenever it tries to access the WSDL @

http://localhost/wsdl/SOAService.wsdl

Here's jax-ws-catalog.xml

<catalog xmlns="urn:oasis:names:tc:entity:xmlns:xml:catalog" prefer="system">
        <system systemId="http://localhost/wsdl/SOAService.wsdl"
                uri="wsdl/SOAService.wsdl"/>
    </catalog>

What you are doing is telling jax-ws that when ever it needs to load WSDL from

http://localhost/wsdl/SOAService.wsdl

, it should load it from local path wsdl/SOAService.wsdl.

Now where should you put wsdl/SOAService.wsdl and jax-ws-catalog.xml ? That's the million dollar question isn't it ?
It should be in the META-INF directory of your application jar.

so something like this

ABCD.jar  
|__ META-INF    
    |__ jax-ws-catalog.xml  
    |__ wsdl  
        |__ SOAService.wsdl

This way you don't even have to override the URL in your client that access the proxy. The WSDL is picked up from within your JAR, and you avoid having to have hard-coded filesystem paths in your code.

More info on jax-ws-catalog.xml http://jax-ws.java.net/nonav/2.1.2m1/docs/catalog-support.html

Hope that helps

这篇关于JAX-WS 客户端:访问本地 WSDL 的正确路径是什么?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！

查看全文

JAX-WS 客户端:访问本地 WSDL 的正确路径是什么? [英] JAX-WS client : what's the correct path to access the local WSDL?

问题描述

相关文章

Java开发最新文章

热门教程

热门工具

登录关闭

JAX-WS 客户端:访问本地 WSDL 的正确路径是什么? [英] JAX-WS client : what&#39;s the correct path to access the local WSDL?

问题描述

相关文章

Java开发最新文章

热门教程

热门工具

登录 关闭

JAX-WS 客户端:访问本地 WSDL 的正确路径是什么? [英] JAX-WS client : what's the correct path to access the local WSDL?

登录关闭