使用while循环计算数字 [英] Counting digits using while loop

问题描述

我最近正在制作一个程序，需要检查用户输入的数字中的位数.结果我做了以下代码:

I was recently making a program which needed to check the number of digits in a number inputted by the user. As a result I made the following code:

int x;    
cout << "Enter a number: ";
cin >> x;
x /= 10;
while(x > 0)
{
  count++;
  x = x/10;
}

据我所知(即使我的经验有限)，它看起来很粗糙，而且相当不雅.

From what I can tell (even with my limited experience) is that it seems crude and rather unelegant.

有没有人知道如何改进此代码(同时不使用内置的 C++ 函数)?

Does anyone have an idea on how to improve this code (while not using an inbuilt c++ function)?

推荐答案

在您的特定示例中，您可以将数字作为字符串读取并计算字符数.

In your particular example you could read the number as a string and count the number of characters.

但对于一般情况，您可以按照自己的方式进行操作，也可以使用以 10 为底的对数.

But for the general case, you can do it your way or you can use a base-10 logarithm.

这里是对数示例:

#include <iostream>
#include <cmath>

using namespace std;

int main()
{
    double n;
    cout << "Enter a number: ";
    cin >> n;

    cout << "Log 10 is " << log10(n) << endl;
    cout << "Digits are " << ceil(log10(fabs(n)+1)) << endl;
    return 0;
}

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