PDO 使用 PDO::FETCH_PROPS_LATE 和 __construct() 调用? [英] PDO using PDO::FETCH_PROPS_LATE and __construct() call?

查看:20
本文介绍了PDO 使用 PDO::FETCH_PROPS_LATE 和 __construct() 调用?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试使用 PHP PDO 创建一个 Setting 对象的新实例调用 __construct() 方法并约束 PDO::FETCH_PROPS_LATE.不幸的是,我收到了这个警告(并且绑定不起作用).

如何将列值传递给构造函数方法?

<块引用>

警告:pdo.php 中的 Setting::__construct() 缺少参数 1.

注意:未定义变量:pdo.php 中的键.

类设置{受保护的 $key, $value, $displayable;公共函数 __construct($key, $value = null, $displayable = 1){$this->key = $key;$this->value = $value;$this->displayable = $displayable >0;}}while($mashup = current($mashup)){$stmt = $dbh->prepare('SELECT `key`, value, displayable从设置 WHERE mashup_id = :id');$stmt->bindParam(':id', $mashup->id, PDO::PARAM_INT);$stmt->execute();$settings = $stmt->fetchAll(PDO::FETCH_CLASS|PDO::FETCH_PROPS_LATE,'环境');}$stmt->closeCursor();

解决方案

您的构造函数中有一个非默认参数 $key:

public function __construct($key, $value = null, $displayable = 1)

所以,当你这样做时:

$settings = $stmt->fetchAll(PDO::FETCH_CLASS|PDO::FETCH_PROPS_LATE,'Setting');

错误:warning: Missing argument 1 for Setting::__construct() in pdo.php 仅针对参数 $key 抛出,因为它不是默认值.>

正确使用fetchAll(PDO::FETCH_CLASS|PDO::FETCH_PROPS_LATE,...是这样的:

$variable = $stmt->fetchAll(PDO::FETCH_CLASS|PDO::FETCH_PROPS_LATE,'班级名称',<构造函数中使用的参数名称数组(按顺序)>);

所以,就你而言:

$variable = $stmt->fetchAll(PDO::FETCH_CLASS|PDO::FETCH_PROPS_LATE,'环境',array('key', 'value', 'displayable');

I'm trying to create a new instance of Setting object calling __construct() method with PHP PDO and constrain PDO::FETCH_PROPS_LATE. Unfortunatly i'm getting this warning (and binding doesn't work).

How can pass column values to the constructor method?

Warning: Missing argument 1 for Setting::__construct() in pdo.php.

Notice: Undefined variable: key in pdo.php.

class Setting
{

    protected $key, $value, $displayable;

    public function __construct($key, $value = null, $displayable = 1)
    {
        $this->key         = $key;
        $this->value       = $value;
        $this->displayable = $displayable > 0;
    }

}

while($mashup = current($mashups))
{
    $stmt = $dbh->prepare('SELECT `key`, value, displayable
        FROM setting WHERE mashup_id = :id');

    $stmt->bindParam(':id', $mashup->id, PDO::PARAM_INT);
    $stmt->execute();

    $settings = $stmt->fetchAll(PDO::FETCH_CLASS|PDO::FETCH_PROPS_LATE,
       'Setting');
}

$stmt->closeCursor();

解决方案

You have a non defaulted parameter $key in your constructor:

public function __construct($key, $value = null, $displayable = 1)

So, when you are doing this:

$settings = $stmt->fetchAll(PDO::FETCH_CLASS|PDO::FETCH_PROPS_LATE,'Setting');

Error: warning: Missing argument 1 for Setting::__construct() in pdo.php is thrown only for parameter $key because it is not defaulted.

The correct use of fetchAll(PDO::FETCH_CLASS|PDO::FETCH_PROPS_LATE,... is like this:

$variable = $stmt->fetchAll(PDO::FETCH_CLASS|PDO::FETCH_PROPS_LATE,
                           'classname', 
                            <array of parameter names(in order) used in constructor>);

So, in your case:

$variable = $stmt->fetchAll(PDO::FETCH_CLASS|PDO::FETCH_PROPS_LATE,
                            'Setting', 
                             array('key', 'value', 'displayable');

这篇关于PDO 使用 PDO::FETCH_PROPS_LATE 和 __construct() 调用?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆