创建新联系人而不是更新现有联系人 [英] New contact creating rather than updating existing contact

问题描述

我正在将我的应用程序与 android 默认联系人应用程序集成.我想在每个联系人详细信息中显示一个选项xyz using MyApp".我可以在帐户"部分看到我的应用程序，并带有同步联系人的选项，但仍然是我的应用不会与现有联系人合并，而是创建一个新联系人并在其中合并.

I am integrating my app with android default Contacts application.I would like to show an option "xyz using MyApp" inside every Contacts Detail.I am able to see my app in Accounts Section with an option to sync Contacts but still my app not merging with existing contacts but instead creating a new contact and merging in it.

performSync() 方法

performSync() method

private static void addContact(ContentResolver contentResolver,int name, int phoneNumber) {
    Log.i("XYZ", "Adding contact: " + name);
    ArrayList<ContentProviderOperation> operationList = new ArrayList<ContentProviderOperation>();

    //Create our RawContact
    ContentProviderOperation.Builder builder = ContentProviderOperation.newInsert(ContactsContract.RawContacts.CONTENT_URI);
    builder.withValue(ContactsContract.RawContacts.ACCOUNT_NAME, name);
    builder.withValue(ContactsContract.RawContacts.ACCOUNT_TYPE, "com.example.xyz.myapplication");
    builder.withValue(ContactsContract.RawContacts.SYNC1, phoneNumber);
    operationList.add(builder.build());

    //Create a Data record of common type 'StructuredName' for our RawContact
    builder = ContentProviderOperation.newInsert(ContactsContract.Data.CONTENT_URI);
    builder.withValueBackReference(ContactsContract.CommonDataKinds.StructuredName.RAW_CONTACT_ID, 0);
    builder.withValue(ContactsContract.Data.MIMETYPE, ContactsContract.CommonDataKinds.StructuredName.CONTENT_ITEM_TYPE);
    builder.withValue(ContactsContract.CommonDataKinds.StructuredName.DISPLAY_NAME, name);
    operationList.add(builder.build());

    //Create a Data record of custom type "vnd.android.cursor.item/vnd.com.example.xyz.myapplication.profile" to display a link to the Last.fm profile
    builder = ContentProviderOperation.newInsert(ContactsContract.Data.CONTENT_URI);
    builder.withValueBackReference(ContactsContract.Data.RAW_CONTACT_ID, 0);
    builder.withValue(ContactsContract.Data.MIMETYPE, "vnd.android.cursor.item/vnd.com.example.xyz.myapplication.profile");
    builder.withValue(ContactsContract.Data.DATA1, phoneNumber);
    builder.withValue(ContactsContract.Data.DATA2, "Last.fm Profile");
    builder.withValue(ContactsContract.Data.DATA3, "View profile");
    operationList.add(builder.build());

    try {
        contentResolver.applyBatch(ContactsContract.AUTHORITY, operationList);
    } catch (Exception e) {
        Log.e("XYZ", "Something went wrong during creation! " + e);
        e.printStackTrace();
    }
}

推荐答案

在您的 addContact 代码中，您缺少告诉 Contacts DB 加入新原始数据的部分-contact 到现有联系人，这样联系人现在将包含您的原始联系人，并且在联系人应用中打开该联系人时将显示您的应用特定行.

in your addContact code you're missing the part that tells Contacts DB to join your new raw-contact into the existing contact, so that contact will now contain your raw-contact and your app-specific line will be shown when opening that contact in the contacts app.

查看有关如何将 RawContact 加入现有联系人的答案:为什么不聚合联系人?

Check this answer on how to join a RawContact into an existing Contact: why won't contacts aggregate?

您可能需要将一些 RawContact ID 传递给您的 addContact 方法，以便它能够将两者连接在一起.

You'll probably need to pass in some RawContact ID to your addContact method so it'll be able to join the two together.

更新

不要将聚合操作与您的 RawContact 插入操作一起应用，让我们尝试分成两个 applyBatch 调用，此外，让我们将新的原始联系人与 ALL 现有的原始联系人，而不仅仅是其中之一.尝试以下代码，确保将现有的 contact-id(不是原始联系人 id)和新的原始联系人 id 传递给它.

Instead of applying the aggregation operation together with your RawContact insert operation, let's try to separate into two applyBatch calls, also, let's aggregate your new raw-contact with ALL existing raw-contacts, not just one of them. Try the following code, make sure you pass to it the existing contact-id (not raw-contact id) and your new raw-contact-id.

private void joinIntoExistingContact(long existingContactId, long newRawContactId) {

    // get all existing raw-contact-ids that belong to the contact-id
    List<Long> existingRawIds = new ArrayList<>();
    Cursor cur = getContentResolver().query(RawContacts.CONTENT_URI, new String[] { RawContacts._ID }, RawContacts.CONTACT_ID + "=" + existingContactId, null, null);
    while (cur.moveToNext()) {
        existingRawIds.add(cur.getLong(0));
    }
    cur.close();
    Log.i("Join", "Found " + existingRawIds.size() + " raw-contact-ids");

    List<ContentProviderOperation> ops = new ArrayList<ContentProviderOperation>();

    // go over all existing raw ids, and join with our new one
    for (Long existingRawId : existingRawIds) {
        Builder builder = ContentProviderOperation.newUpdate(AggregationExceptions.CONTENT_URI);
        builder.withValue(AggregationExceptions.TYPE, AggregationExceptions.TYPE_KEEP_TOGETHER);
        builder.withValue(AggregationExceptions.RAW_CONTACT_ID1, newRawContactId);
        builder.withValue(AggregationExceptions.RAW_CONTACT_ID2, existingRawId);
        ops.add(builder.build());
    }

    contentResolver.applyBatch(ContactsContract.AUTHORITY, ops);
}

附言
不要打开两个重复的问题，一个就够了.

另一个更新

您似乎对 ID 有点困惑.

You seem to have some confusion about IDs.

有 Data ID、RawContact ID 和 Contact ID.

There are Data IDs, RawContact IDs, and Contact IDs.

CommonDataKinds.Phone._ID 将返回一个 Data ID，标识数据表中存储该电话号码的特定行.

CommonDataKinds.Phone._ID will return a Data ID, identifying the specific row in the Data table in which that phone number is stored.

您也可以从 Phone 表中获取其他 ID，使用:CommonDataKinds.Phone.RAW_CONTACT_IDCommonDataKinds.Phone.CONTACT_ID

You can get a from the Phone table the other IDs as well, use: CommonDataKinds.Phone.RAW_CONTACT_ID CommonDataKinds.Phone.CONTACT_ID

您可以在此处阅读更多信息:https://stackoverflow.com/a/50084029/819355

You can read more here: https://stackoverflow.com/a/50084029/819355

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