如何显示共同的行(反向差异)? [英] How can I show lines in common (reverse diff)?

问题描述

我有一系列文本文件，我想知道它们的共同行而不是它们之间不同的行.命令行 Unix 或 Windows 都可以.

I have a series of text files for which I'd like to know the lines in common rather than the lines which are different between them. Command line Unix or Windows is fine.

文件foo:

linux-vdso.so.1 =>  (0x00007fffccffe000)
libvlc.so.2 => /usr/lib/libvlc.so.2 (0x00007f0dc4b0b000)
libvlccore.so.0 => /usr/lib/libvlccore.so.0 (0x00007f0dc483f000)
libc.so.6 => /lib/libc.so.6 (0x00007f0dc44cd000)

文件栏:

libkdeui.so.5 => /usr/lib/libkdeui.so.5 (0x00007f716ae22000)
libkio.so.5 => /usr/lib/libkio.so.5 (0x00007f716a96d000)
linux-vdso.so.1 =>  (0x00007fffccffe000)

因此，鉴于上面的这两个文件，所需实用程序的输出类似于 file1:line_number, file2:line_number == 匹配文本(只是一个建议；我真的不在乎语法是什么):

So, given these two files above, the output of the desired utility would be akin to file1:line_number, file2:line_number == matching text (just a suggestion; I really don't care what the syntax is):

foo:1, bar:3 == linux-vdso.so.1 =>  (0x00007fffccffe000)

推荐答案

在 *nix 上，您可以使用 通讯.问题的答案是:

On *nix, you can use comm. The answer to the question is:

comm -1 -2 file1.sorted file2.sorted 
# where file1 and file2 are sorted and piped into *.sorted

以下是 comm 的完整用法:

Here's the full usage of comm:

comm [-1] [-2] [-3 ] file1 file2
-1 Suppress the output column of lines unique to file1.
-2 Suppress the output column of lines unique to file2.
-3 Suppress the output column of lines duplicated in file1 and file2. 

另请注意，在使用 comm 之前对文件进行排序很重要，如手册页中所述.

Also note that it is important to sort the files before using comm, as mentioned in the man pages.

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