从 shell 脚本启动 Web 浏览器的干净方法? [英] Clean way to launch the web browser from shell script?

问题描述

在 bash 脚本中，我需要启动用户 Web 浏览器.似乎有很多方法可以做到这一点:

In a bash script, I need to launch the user web browser. There seems to be many ways of doing this:

• $BROWSER
• xdg-open
• gnome-open 在 GNOME 上
• www-browser
• x-www-browser
• ...

是否有一种比其他方法更标准的方法可以在大多数平台上运行，或者我应该使用这样的方法:

Is there a more-standard-than-the-others way to do this that would work on most platforms, or should I just go with something like this:

#/usr/bin/env bash

if [ -n $BROWSER ]; then
  $BROWSER 'http://wwww.google.com'
elif which xdg-open > /dev/null; then
  xdg-open 'http://wwww.google.com'
elif which gnome-open > /dev/null; then
  gnome-open 'http://wwww.google.com'
# elif bla bla bla...
else
  echo "Could not detect the web browser to use."
fi

推荐答案

xdg-open 是标准化的，应该在大多数发行版中可用.

xdg-open is standardized and should be available in most distributions.

否则:

1. eval 是邪恶的，不要使用它.
2. 引用你的变量.
3. 以正确的方式使用正确的测试运算符.

1. eval is evil, don't use it.
2. Quote your variables.
3. Use the correct test operators in the correct way.

这是一个例子:

#!/bin/bash
if which xdg-open > /dev/null
then
  xdg-open URL
elif which gnome-open > /dev/null
then
  gnome-open URL
fi

也许这个版本稍微好一点(仍未测试):

Maybe this version is slightly better (still untested):

#!/bin/bash
URL=$1
[[ -x $BROWSER ]] && exec "$BROWSER" "$URL"
path=$(which xdg-open || which gnome-open) && exec "$path" "$URL"
echo "Can't find browser"

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