android中WebView的HTTP POST响应 [英] HTTP POST response into WebView in android

问题描述

我正在尝试使用 HTTP 连接到页面邮政.我做了一个 http 帖子来创建一个网络视图.我需要从 webview 重定向到另一个页面.但是当点击继续按钮时会抛出异常.

I'm attempting to connect to the page using an HTTP Post. I do an http post for creating a webview. i need to redirect to another page from the webview. But when the continue button is clicked exception is thrown .

我的代码是

public class ZHttpPostProjActivity extends Activity {
    /** Called when the activity is first created. */

    private WebView mWebView;
    private ProgressDialog progressBar;
    private static final String TAG = "ZHttpPostProjActivity";

    @Override
    public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.web_view);

    mWebView = (WebView) findViewById(R.id.webview);
    WebSettings webSettings = mWebView.getSettings();

    webSettings.setJavaScriptEnabled(true);
    webSettings.setDomStorageEnabled(true);

    progressBar = ProgressDialog.show(ZHttpPostProjActivity.this, "",
        "Loading...");

    postData();
    }


    private final String URL_REGISTER = "https://www.paypal.com/checkout";

    public void postData() {

    BufferedReader bufferedReader = null;

    try {
        List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
        nameValuePairs.add(new BasicNameValuePair("username", "username"));
        nameValuePairs.add(new BasicNameValuePair("password", "password"));

        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost(URL_REGISTER);
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs,
            HTTP.UTF_8));

        HttpResponse response = httpclient.execute(httppost);

        bufferedReader = new BufferedReader(new InputStreamReader(response
            .getEntity().getContent()));
        StringBuffer stringBuffer = new StringBuffer("");
        String line = "";
        String LineSeparator = System.getProperty("line.separator");
        while ((line = bufferedReader.readLine()) != null) {
        stringBuffer.append(line + LineSeparator);
        }
        bufferedReader.close();

        String webData = stringBuffer.toString();
        Log.i(TAG + "web data : ", webData);

        // String webData = new
        // BasicResponseHandler().handleResponse(response);

        Log.i(TAG, "Httppost.getURI().toString(): "
            + httppost.getURI().toString());

        mWebView.setWebViewClient(new WebViewClient() {
        public boolean shouldOverrideUrlLoading(WebView view, String url) {
            Log.i(TAG, "Processing webview url click...");
            view.loadUrl(url);
            return true;
        }

        public void onPageFinished(WebView view, String url) {

            Log.i(TAG, "Finished loading URL: " + url);
            if (progressBar.isShowing()) {
            progressBar.dismiss();
            }
        }

        public void onReceivedError(WebView view, int errorCode,
            String description, String failingUrl) {
            Log.e(TAG, "Error: " + description + " 
 errorCode: "
                + errorCode + "
  failingUrl: " + failingUrl);

        }
        });

        // mWebView.loadUrl(httppost.getURI().toString());
        mWebView.loadData(webData, "text/html", "UTF-8");
        mWebView.loadDataWithBaseURL(httppost.getURI().toString(), webData,
            "text/html", HTTP.UTF_8, null);

    } catch (Exception ex) {
        ex.printStackTrace();
    }

    }

点击 webview 中的继续按钮时抛出异常

While Clicking the continue button in the webview an exception is thrown

02-21 11:42:38.539: E/webviewdatabase(2848): Failed in setFormData
02-21 11:42:38.539: E/webviewdatabase(2848): java.net.MalformedURLException: Unknown protocol: about
02-21 11:42:38.539: E/webviewdatabase(2848):    at java.net.URL.<init>(URL.java:288)
02-21 11:42:38.539: E/webviewdatabase(2848):    at java.net.URL.<init>(URL.java:157)
02-21 11:42:38.539: E/webviewdatabase(2848):    at android.webkit.WebViewDatabase.setFormData(WebViewDatabase.java:1032)
02-21 11:42:38.539: E/webviewdatabase(2848):    at android.webkit.BrowserFrame.loadStarted(BrowserFrame.java:384)
02-21 11:42:38.539: E/webviewdatabase(2848):    at android.webkit.JWebCoreJavaBridge.sharedTimerFired(Native Method)
02-21 11:42:38.539: E/webviewdatabase(2848):    at android.webkit.JWebCoreJavaBridge.fireSharedTimer(JWebCoreJavaBridge.java:91)
02-21 11:42:38.539: E/webviewdatabase(2848):    at android.webkit.JWebCoreJavaBridge.handleMessage(JWebCoreJavaBridge.java:108)
02-21 11:42:38.539: E/webviewdatabase(2848):    at android.os.Handler.dispatchMessage(Handler.java:99)
02-21 11:42:38.539: E/webviewdatabase(2848):    at android.os.Looper.loop(Looper.java:123)
02-21 11:42:38.539: E/webviewdatabase(2848):    at android.webkit.WebViewCore$WebCoreThread.run(WebViewCore.java:673)
02-21 11:42:38.539: E/webviewdatabase(2848):    at java.lang.Thread.run(Thread.java:1019)
02-21 11:42:41.324: E/cache(2848): illegal expires: Sat, Jan 01 2000 01:01:01 GMT

推荐答案

像这样使用

WebView webview = new WebView(this);
setContentView(webview);
byte[] post = EncodingUtils.getBytes("postvariable=value&nextvar=value2", "BASE64");
webview.postUrl("http://www.geenie.nl/AnHeli/mobile/ranking/demo/index.php", post);

这篇关于android中WebView的HTTP POST响应的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！