在 Hive 中将字符串转换为时间戳 [英] Convert string to timestamp in Hive

问题描述

我的 Hive 表中有时间戳的以下字符串表示形式:

I have the following string representation of a timestamp in my Hive table:

20130502081559999

我需要将其转换为这样的字符串:

I need to convert it to a string like so:

2013-05-02 08:15:59

我尝试了以下({code} >>> {result}):

I have tried following ({code} >>> {result}):

from_unixtime(unix_timestamp('20130502081559999', 'yyyyMMddHHmmss')) >>> 2013-05-03 00:54:59
from_unixtime(unix_timestamp('20130502081559999', 'yyyyMMddHHmmssMS')) >>> 2013-09-02 08:15:59
from_unixtime(unix_timestamp('20130502081559999', 'yyyyMMddHHmmssMS')) >>> 2013-05-02 08:10:39

转换为时间戳，然后转换为 unixtime 似乎很奇怪，这样做的正确方法是什么?

Converting to a timestamp and then unixtime seems weird, what is the proper way to do this?

编辑我想通了.

from_unixtime(unix_timestamp(substr('20130502081559999',1,14), 'yyyyMMddHHmmss')) >>> 2013-05-02 08:15:59

或

from_unixtime(unix_timestamp('20130502081559999', 'yyyyMMddHHmmssSSS')) >>> 2013-05-02 08:15:59

还是...有更好的方法吗?

Still... Is there a better way?

推荐答案

不知道你说的更好的方式"是什么意思，但你总是可以编写自己的函数来处理日期转换.

Not sure what you mean by "better way" but you can always write your own function to handle the date conversion.

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