使用 HiveQL 分解结构数组 [英] Exploding Array of Struct using HiveQL

问题描述

CREATE TABLE IF NOT EXISTS Table2
(
USER_ID BIGINT,
PURCHASED_ITEM ARRAY<STRUCT<PRODUCT_ID: BIGINT,TIMESTAMPS:STRING>>
) ROW FORMAT
 DELIMITED FIELDS TERMINATED BY '-'
 collection items terminated by ','
 map keys terminated by ':'
 LINES TERMINATED BY '
'
 STORED AS TEXTFILE
 LOCATION '/user/rj/output2';

以下是表2中的数据

1345653-110909316904:1341894546,221065796761:1341887508

我可以通过使用下面的查询来分解上面的数据，它适用于上面的数据-

I can explode the above data by using this below query and it works fine for above data-

SELECT  * FROM (select user_id, prod_and_ts.product_id as product_id,
prod_and_ts.timestamps as timestamps FROM table2 LATERAL VIEW
explode(purchased_item) exploded_table as prod_and_ts) prod_and_ts;

我会得到这样的输出，这很好-

And I will get output like this which is fine-

1345653                                110909316904     1341894546
1345653                                221065796761     1341887508

但在某些情况下，我在下表中有这样的数据，对于相同的 product_id- 用井号附加多个时间戳-

But in some cases I have data in the table below like this, multiple timestamp appended by pound sign for same product_id-

1345653-110909316904:1341894546#1341885695,221065796761:1341887508#1341885453

我需要使用 HiveQL 查询对上述数据进行这样的输出-

And I need output like this for above data using the HiveQL query-

1345653                                110909316904     1341894546
1345653                                110909316904    1341885695
1345653                                221065796761     1341887508
1345653                                221065796761    1341885453

这有可能以某种方式做到这一点吗?

Is this possible to do this somehow?

任何建议将不胜感激.?

Any suggestions will be appreciated.?

P.S 几天前我问过这个问题，但在那种情况下数据不同，现在数据完全不同，我需要类似的输出.

P.S I ask this question few days back, but in that case data was different and now data is totally different and I need similar output.

推荐答案

您可以使用函数 regexp_replace 或 regex_extract 来仅获取产品 ID.试试这个:

You can use the function regexp_replace or regex_extract to get only the product id. Try this:

SELECT  * FROM (select user_id, prod_and_ts.product_id as product_id,
regex_replace(prod_and_ts.timestamps, "#\d*", "")  as timestamps FROM table2 LATERAL VIEW
explode(purchased_item) exploded_table as prod_and_ts) prod_and_ts;

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