int() 参数必须是字符串或数字,而不是“SimpleLazyObject" [英] int() argument must be a string or a number, not 'SimpleLazyObject'
问题描述
我收到错误消息,
TypeError at/save/int() 参数必须是字符串或数字,而不是'SimpleLazyObject'
TypeError at /save/ int() argument must be a string or a number, not 'SimpleLazyObject'
在执行以下表单时.
views.py
def bookmark_save_page(request):
if request.method == 'POST':
form = BookmarkSaveForm(request.POST)
if form.is_valid():
# create or get link
link, dummy = Link.objects.get_or_create(
url = form.cleaned_data['url']
)
# create or get bookmark
bookmark, created = Bookmark.objects.get_or_create(
user=request.user,
link=link
)
# update bookmarks title
bookmarks.title = form.cleaned_data['title']
# if the bookmark is being updated, clear old tag list.
if not created:
bookmark.tag_set.clear()
# create new tag list
tag_names = form.cleaned_data['tags'].split()
for tag_name in tag_names:
tag, dummy = Tag.objects.get_or_create(name=tag_name)
bookmark.tag_set.add(tag)
# save bookmark to database.
bookmark.save()
return HttpResponseRedirect(
'/user/%s/' % request.user.username
)
else:
form = BookmarkSaveForm()
variables = RequestContext(request, {
'form': form
})
return render_to_response('bookmark_save.html', variables)
<小时>
我以为我出错了,因为我在
I thought I got error because I passed link at
bookmark, created = Bookmark.objects.get_or_create(
user=request.user,
link=link
)
但是我不知道如何解决它.我该如何解决?
But I can not figure out how to fix it. How can I fix it?
推荐答案
可能的原因是您设置了 user = request.user
,其中 request.user 不是真正的 User 对象,但是一个 SimpleLazyObject 实例.参见 django:django.utils.functional.SimpleLazyObject 的目的? 了解更多详情,但使用 request.user.id
应该可以解决您的问题.
The likely cause is that you're setting user = request.user
, where request.user is not a real User object, but a SimpleLazyObject instance. See django: Purpose of django.utils.functional.SimpleLazyObject? for more details, but using request.user.id
should fix your issue.
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