通过 django 中的 url 传递列表 [英] Passing a list through url in django

问题描述

我想通过 url 传递一个列表.但是当我尝试时，我遇到了一些错误.那我该怎么做.有人请帮助我..

I want to pass a list through the url. But when i tried, i got some errors. So how can i do that. Somebody please help me..

这是我的看法

def add_student(request):

    if request.method == 'POST':
        student_list = []
        student_name = request.POST.getlist('student_name')
        student_phone = request.POST.getlist('student_phone')

        zipped = zip(student_name,student_phone)

        for student_name,student_phone in zipped:

            student_object = Student(
                                student_name=student_name,
                                student_phone=student_phone
                            )
            student_object.save()

            student_list.append(student_object.id)

        return HttpResponseRedirect(reverse('students:view_students', args=student_list))
**# in the above code it throwing some errors** 
    else:
        return render(request,'students/add_student.html')


def view_students(request,student_list=None):
    if student_list:
        instances = Student.objects.filter(id__in=student_list)
    else:
        instances = Student.objects.filter()
    context = {}
    context['instances'] = instances

    return render(request,'students/view_all_student.html',context)

这是我的网址:

url(r'^view-students/(?P<student_list>w+)/$',views.view_students, name='view_students'),

这是我得到的错误.

NoReverseMatch at /app/product/add-product/

Reverse for 'view_products' with arguments '(14, 15)' and keyword arguments '{}' not found. 1 pattern(s) tried: [u'app/product/view-products/(?P<pd_list>.*)/$']

这里 (14,15) 是列表项.

here (14,15) are the list items.

如果问题不正确.有人请纠正问题.

If the question is not correct. Somebody please correct the question.

推荐答案

如果你只想渲染一个列表，你应该这样做.

If all you want to do is render a list you should just do that.

def add_student(request):
    if request.method == 'POST':
        student_list = []
        student_name = request.POST.getlist('student_name')
        student_phone = request.POST.getlist('student_phone')

        zipped = zip(student_name,student_phone)

        for student_name,student_phone in zipped:
            student = Student.objects.create(student_name=student_name,
                                             student_phone=student_phone)
            student_list.append(student)

        return render(request,'students/view_all_student.html', {'instances': student_list})
    else:
        return render(request,'students/add_student.html')

但是，您的问题似乎与用户重复发布此请求有关.为了解决这个问题，您可以将它们作为获取参数传递

However, Your issue seems to be concerned with users double posting this request. To remedy this you could pass them as a get parameter

def add_student(request):
    if request.method == 'POST':
        student_list = []
        student_name = request.POST.getlist('student_name')
        student_phone = request.POST.getlist('student_phone')

        zipped = zip(student_name,student_phone)

        for student_name,student_phone in zipped:
            student = Student.objects.create(student_name=student_name,
                                             student_phone=student_phone)
            student_list.append(str(student.id))

        redirect = HttpResponseRedirect(reverse('students:view_students'))
        redirect['Location'] += '&'.join(['students={}'.format(x) for x in student_list]))
        return redirect
    else:
        return render(request,'students/add_student.html')

def view_students(request):
    students = request.GET.getlist('students')
    if students:
        students = [int(x) for x in students]
        instances = Student.objects.filter(id__in=students)

这篇关于通过 django 中的 url 传递列表的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！