如何分解元组以便它可以作为参数列表传递? [英] How can I explode a tuple so that it can be passed as a parameter list?

问题描述

假设我有一个这样的方法定义:

Let's say I have a method definition like this:

def myMethod(a, b, c, d, e)

然后，我有一个变量和一个像这样的元组:

Then, I have a variable and a tuple like this:

myVariable = 1
myTuple = (2, 3, 4, 5)

有没有一种方法可以传递爆炸元组，以便我可以将其成员作为参数传递?像这样的东西(虽然我知道这不会起作用，因为整个元组被认为是第二个参数):

Is there a way I can pass explode the tuple so that I can pass its members as parameters? Something like this (although I know this won't work as the entire tuple is considered the second parameter):

myMethod(myVariable, myTuple)

如果可能，我想避免单独引用每个元组成员...

I'd like to avoid referencing each tuple member individually if possible...

推荐答案

您正在寻找 参数解包 operator *:

You are looking for the argument unpacking operator *:

myMethod(myVariable, *myTuple)

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