java.awt.Color.getColor(String colorName) 是如何工作的? [英] How does java.awt.Color.getColor(String colorName) work?

问题描述

我正在尝试按名称获取颜色，但遇到了 转换Java 中的 String to Color，建议使用 java.awt.getColor.

I'm trying to get colors by name, and I came across Converting a String to Color in Java, which suggests using java.awt.getColor.

我不知道如何将它作为字符串传递.以下

I can't work out what to pass it as a string though. The following

System.out.println( java.awt.Color.getColor( "black", Color.red ) );

打印出来

java.awt.Color[r=255,g=0,b=0]

java.awt.Color[r=255,g=0,b=0]

即它在那里使用默认颜色.

i.e. it is going with the default color in there.

我已经把它放在一个文本框中，并尝试了其他大写字母等.这些文档在这里不是很有帮助.任何人都可以建议放入什么魔法字符串?

I've put this in a text box, and tried alternative capitalisations etc. The docs aren't very helpful here. Can anyone suggest what magic strings to put in?

推荐答案

未接受的答案使用 Color.getColor.此方法从可能存在或可能不存在的系统属性中读取.你不应该使用这种方法.

The non-accepted answer uses Color.getColor. This method reads from system properties which may or may not be present. You should not use this method.

相反，您应该使用 upvoted 反射方法来查找 Color 类的静态成员.要么这样做，要么您应该导入自己的颜色数据库，该数据库将字符串名称映射到 RGB 值.

Instead, you should use the upvoted reflection method to find the static member of the Color class. Either this, or you should import your own color database which maps string names to RGB values.

Color color;
try {
    Field field = Color.class.getField("yellow");
    color = (Color)field.get(null);
} catch (Exception e) {
    color = null; // Not defined
}

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