Flask SQLAlchemy 使用“不等于"查询列 [英] Flask SQLAlchemy querying a column with "not equals"
本文介绍了Flask SQLAlchemy 使用“不等于"查询列的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我可以查询我的 Seat
表中没有分配邀请的所有座位:
seats = Seat.query.filter_by(invite=None).all()
然而,当查询所有分配了邀请的席位时,我得到一个NameError
:
seats = Seat.query.filter_by(invite!=None).all()
NameError: name 'invite' 未定义
这是我的Seat
课程:
class Seat(db.Model):id = db.Column(db.Integer, primary_key=True)邀请 ID = db.Column(db.Integer, db.ForeignKey('invite.id'))邀请 = db.relationship('邀请',backref=db.backref('伙计',lazy='dynamic'))
如何查询所有者不为空的所有座位?
解决方案
filter_by()
方法采用关键字参数序列,因此您必须始终将 =
与它一起使用.>
您想使用 filter()
允许 !=
的方法:
seats = Seat.query.filter(Seat.invite != None).all()
I can query my Seat
table for all seats where there is no invite assigned:
seats = Seat.query.filter_by(invite=None).all()
However, when querying for all seats that have an invite assigned, I get a NameError
:
seats = Seat.query.filter_by(invite!=None).all()
NameError: name 'invite' is not defined
Here is my Seat
class:
class Seat(db.Model):
id = db.Column(db.Integer, primary_key=True)
invite_id = db.Column(db.Integer, db.ForeignKey('invite.id'))
invite = db.relationship('Invite',
backref=db.backref('folks', lazy='dynamic'))
How can I query for all seats where the owner is not blank?
解决方案
The filter_by()
method takes a sequence of keyword arguments, so you always have to use =
with it.
You want to use the filter()
method which allows for !=
:
seats = Seat.query.filter(Seat.invite != None).all()
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