构造函数覆盖可能吗? [英] Is Constructor Overriding Possible?

问题描述

我所知道的是，编译器在字节码中编写了一个默认的无参数构造函数.但是如果我们自己编写它，该构造函数将被自动调用.这种现象是构造函数覆盖吗?

What i know is, the compiler writes a default no argument constructor in the byte code. But if we write it ourselves, that constructor is called automatically. Is this phenomena a constructor overriding?

推荐答案

您所描述的内容并不重要.如果不指定默认构造函数，则编译器将创建一个默认构造函数.如果它是一个子类，它将调用默认的父构造函数(super())，它还将所有实例变量初始化为由类型的默认值确定的默认值(0 表示数字类型，false 表示布尔值，或 null用于对象).

What you describe isn't overriding. If you don't specify a default constructor, the compiler will create a default constructor. If it's a subclass, it will call the default parent constructor(super()), it will also initialize all instance variables to a default value determined by the type's default value(0 for numeric types, false for booleans, or null for objects).

当子类具有相同的名称、参数数量/类型以及与超类的实例方法相同的返回类型.在这种情况下，子类将覆盖超类的方法.有关在此处进行覆盖的信息.

Overriding happens when a subclass has the same name, number/type of parameters, and the same return type as an instance method of the superclass. In this case, the subclass will override the superclass's method. Information on overriding here.

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