有没有办法确定 Lua 函数的签名? [英] Is there a way to determine the signature of a Lua function?

问题描述

最近，Lee Baldwin 展示了如何编写 通用可变参数记忆函数.我认为返回一个只需要一个参数的更简单的函数会更好.这是我完全虚假的尝试:

Recently, Lee Baldwin showed how to write a generic, variable argument memoize function. I thought it would be better to return a simpler function where only one parameter is required. Here is my total bogus attempt:

local function memoize(f)
   local cache = {}

   if select('#', ...) == 1 then
      return function (x)
                if cache[x] then
                   return cache[x]
                else
                   local y = f(x)
                   cache[x] = y
                   return y
                end
              end
   else
      return function (...)
                local al = varg_tostring(...)
                if cache[al] then
                   return cache[al]
                else
                   local y = f(...)
                   cache[al] = y
                   return y
                end
             end
   end
end

显然，select('#', ...) 在这种情况下失败了，无论如何都不会真正做我想做的事.有什么办法可以在memoize里面告诉f期望多少个参数?

Obviously, select('#', ...) fails in this context and wouldn't really do what I want anyway. Is there any way to tell inside memoize how many arguments f expects?

如果您确定，否"是一个很好的答案.使用两个独立的 memoize 功能没什么大不了的.

"No" is a fine answer if you know for sure. It's not a big deal to use two separate memoize functions.

推荐答案

我想你可以进入调试信息并从源代码中确定这一点，但基本上它是不"，抱歉.

I guess you could go into the debug info and determine this from the source-code, but basically it's a "no", sorry.

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