获取word文档的页面 [英] Get pages of word document

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本文介绍了获取word文档的页面的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我正在尝试通过 Microsoft.Office.Interop.Word 获取 MSWord 文档的所有页面(我在 VS2012 中使用 C#).我想得到的是 List Pages,其中 index 是页数.我明白(至少我是这么认为的)没有直接的方法可以做到这一点.所以我想出了类似的东西:

I'm trying to get all pages of MSWord document via Microsoft.Office.Interop.Word (I'm using C# in VS2012). What I would like to get is List< String > Pages, where index is the number of page. I understand (at least I think so) that there is no direct way to do that. So I came up with something like that:

        List<String> Pages = new List<String>();
        int NumberOfPreviousPage = -1;
        int NumberOfPage = -1;
        string InnerText = "";
        for (int i = 0; i < Doc.Paragraphs.Count; i++)
        {
            Paragraph CurrentParagraph = Doc.Paragraphs[i + 1];
            InnerText = CurrentParagraph.Range.Text;
            NumberOfPage = CurrentParagraph.Range.get_Information(WdInformation.wdActiveEndPageNumber);
            if (NumberOfPage == NumberOfPreviousPage)
                Pages[Pages.Count - 1] += String.Format("
{0}", InnerText);
            else
            {
                Pages.Add(InnerText);
                NumberOfPreviousPage = NumberOfPage;
            }
        }

但是,当算法到达从一页开始并在另一页结束的段落时,它决定该段落应该在下一页.我想在页面之间拆分此段落,但我不知道如何检测必须拆分的位置.

But, when algorithm gets to paragraph, which starts on one page and ends on another, it decides that paragraph should be on next page. I want to split this paragraph between pages, but I don't know how to detect where I have to do the split.

推荐答案

最终,我完成了这个,并且它有效(它很蹩脚,很丑,但它做了它应该做的):

Eventually, I finished up with this, and it works (it's lame, it's ugly, but it does what it should):

public string[] GetPagesDoc(object Path)
    {
        List<string> Pages = new List<string>();

        // Get application object
        Microsoft.Office.Interop.Word.Application WordApplication = new Microsoft.Office.Interop.Word.Application();

        // Get document object
        object Miss = System.Reflection.Missing.Value;
        object ReadOnly = false;
        object Visible = false;
        Document Doc = WordApplication.Documents.Open(ref Path, ref Miss, ref ReadOnly, ref Miss, ref Miss, ref Miss, ref Miss, ref Miss, ref Miss, ref Miss, ref Miss, ref Visible, ref Miss, ref Miss, ref Miss, ref Miss);

        // Get pages count
        Microsoft.Office.Interop.Word.WdStatistic PagesCountStat = Microsoft.Office.Interop.Word.WdStatistic.wdStatisticPages;
        int PagesCount = Doc.ComputeStatistics(PagesCountStat, ref Miss);

        //Get pages
        object What = Microsoft.Office.Interop.Word.WdGoToItem.wdGoToPage;
        object Which = Microsoft.Office.Interop.Word.WdGoToDirection.wdGoToAbsolute;
        object Start;
        object End;
        object CurrentPageNumber;
        object NextPageNumber;

        for (int Index = 1; Index < PagesCount + 1; Index++)
        {
            CurrentPageNumber = (Convert.ToInt32(Index.ToString()));
            NextPageNumber = (Convert.ToInt32((Index+1).ToString()));

            // Get start position of current page
            Start = WordApplication.Selection.GoTo(ref What, ref Which, ref CurrentPageNumber, ref Miss).Start;

            // Get end position of current page                                
            End = WordApplication.Selection.GoTo(ref What, ref Which, ref NextPageNumber, ref Miss).End;

            // Get text
            if (Convert.ToInt32(Start.ToString()) != Convert.ToInt32(End.ToString()))
                Pages.Add(Doc.Range(ref Start, ref End).Text);
            else
                Pages.Add(Doc.Range(ref Start).Text);
        }
            return Pages.ToArray<string>();
    }

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