使用python请求模块在单个请求中上传多个文件 [英] Uploading multiple files in a single request using python requests module

问题描述

Python requests 模块 提供了关于如何在单个请求:

The Python requests module provides good documentation on how to upload a single file in a single request:

 files = {'file': open('report.xls', 'rb')}

我尝试通过使用此代码来扩展该示例以尝试上传多个文件:

I tried extending that example by using this code in an attempt to upload multiple files:

 files = {'file': [open('report.xls', 'rb'), open('report2.xls, 'rb')]}

但它导致了这个错误:

 File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/urllib.py",      line 1052, in splittype
 match = _typeprog.match(url)
 TypeError: expected string or buffer

是否可以使用此模块在单个请求中上传文件列表，以及如何上传?

Is it possible to upload a list of files in a single request using this module, and how?

推荐答案

要在单个请求中上传具有相同键值的文件列表，您可以创建一个元组列表，以每个元组中的第一项作为键值和文件对象作为第二个:

To upload a list of files with the same key value in a single request, you can create a list of tuples with the first item in each tuple as the key value and the file object as the second:

files = [('file', open('report.xls', 'rb')), ('file', open('report2.xls', 'rb'))]

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