带有请求的 POST XML 文件 [英] POST XML file with requests

问题描述

我得到:

<error>You have an error in your XML syntax...

当我运行这个 python 脚本时，我刚刚写了(我是新手)

when I run this python script I just wrote (I'm a newbie)

import requests

xml = """xxx.xml"""

headers = {'Content-Type':'text/xml'}

r = requests.post('https://example.com/serverxml.asp', data=xml)

print (r.content);

这里是xxx.xml的内容

Here is the content of the xxx.xml

<xml>
<API>4.0</API>
<action>login</action>
<password>xxxx</password>
<license_number>xxxxx</license_number>
<username>[e-mail]</username>
<training>1</training>
</xml>

我知道 xml 是有效的，因为我对 perl 脚本使用了相同的 xml，并且正在打印内容.

I know that the xml is valid because I use the same xml for a perl script and the contents are being printed back.

任何帮助将不胜感激，因为我对 python 非常陌生.

Any help will greatly appreciated as I am very new to python.

推荐答案

您想将 XML 数据从文件提供给 requests.post.但是，此功能不会为您打开文件.它希望您将文件对象传递给它，而不是文件名.您需要在调用 requests.post 之前打开该文件.

You want to give the XML data from a file to requests.post. But, this function will not open a file for you. It expects you to pass a file object to it, not a file name. You need to open the file before you call requests.post.

试试这个:

import requests

# Set the name of the XML file.
xml_file = "xxx.xml"

headers = {'Content-Type':'text/xml'}

# Open the XML file.
with open(xml_file) as xml:
    # Give the object representing the XML file to requests.post.
    r = requests.post('https://example.com/serverxml.asp', data=xml, headers=headers)

print (r.content);

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