java中强制转换的优先级是什么? [英] What is the priority of casting in java?

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问题描述

如果我有一行类似于

int s = (double) t/2   

int s = (double) (t/2)

int s = ((double) t)/2

?

推荐答案

这应该会让事情更清楚一些. 简而言之,强制转换优先于除法运算,因此它给出的输出相同

This should make things a bit clearer. Simply put, a cast takes precedence over a division operation, so it would be the same thing as give the same output as

int s = ((double)t) / 2;

正如 knoight 所指出的,这在技术上与没有括号的操作不同,因为它们也有优先级.但是,就本示例而言,它将提供相同的结果,并且在所有意图和目的上都是等效的.

As knoight has pointed out, this is not technically the same operation as it would be without the parentheses, since they have a priority as well. However, for the purposes of this example, it will offer the same result, and is for all intents and purposes equivalent.

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