Python 中的缩进错误 [英] Indentation Error in Python
本文介绍了Python 中的缩进错误的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我无法编译,因为我的代码中有这部分:
I can't compile because of this part in my code:
if command == 'HOWMANY':
opcodegroupr = "A0"
opcoder = "85"
elif command == 'IDENTIFY':
opcodegroupr = "A0"
opcoder = "81"
我有这个错误:
Sorry: IndentationError: ('unindent does not match any external indentation level', ('wsn.py', 1016, 30, " elif command == 'IDENTIFY': "))
Sorry: IndentationError: ('unindent does not match any outer indentation level', ('wsn.py', 1016, 30, " elif command == 'IDENTIFY': "))
但我没有看到任何缩进错误.可能是什么问题?
But I don't see any indentation error. What can be the problem?
推荐答案
如有疑问,请更改您的编辑器,使制表符和空格可见.让编辑器将所有制表符解析为 4 个空格也是一个很好的主意.
In doubt change your editor to make tabs and spaces visible. It is also a very good idea to have the editor resolve all tabs to 4 spaces.
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