Java中十进制转二进制 [英] Converting decimal to binary in Java

问题描述

我正在尝试编写一个将数字转换为二进制的代码，这就是我所写的.它在 Eclipse 中给了我几个错误，我不明白.那有什么问题?还有其他建议吗?我想学习并听取有关修复它的任何评论.谢谢.

I'm trying to write a code that converts a number to binary, and this is what I wrote. It gives me couple of errors in Eclipse, which I don't understand. What's wrong with that? Any other suggestions? I'd like to learn and hear for any comments for fixing it. Thank you.

public class NumberConverte {
  public static void main(String[] args) {
    int i = Integer.parseInt(args);
    public static void Binary(int int1){
      System.out.println(int1 + "in binary is");
      do {
        System.out.println(i mod 2);
      } while (int1>0);
    }
  }
}

错误信息:

1. Integer 类型中的方法 parseInt(String) 不适用于参数 (String[])
2. 此行有多个标记
   • 标记(", ; 预期的语法错误
   • 标记)"上的语法错误，；预期
   • void 是变量 Binary
   的无效类型

1. The method parseInt(String) in the type Integer is not applicable for the arguments (String[])
2. Multiple markers at this line
   • Syntax error on token "(", ; expected
   • Syntax error on token ")", ; expected
   • void is an invalid type for the variable Binary

• 标记mod"的语法错误，无效的 AssignmentOperator
• 标记mod"的语法错误，无效的 AssignmentOperator.

推荐答案

Integer.toBinaryString(int) 应该可以解决问题！

顺便说一下，如果您使用的是 Eclipse，请更正您的语法，我敢肯定他会抱怨很多错误.

And by the way, correct your syntax, if you're using Eclipse I'm sure he's complaining about a lot of error.

工作代码:

public class NumberConverter {
   public static void main(String[] args) {
       int i = Integer.parseInt(args[0]);
       toBinary(i);
   }

   public static void toBinary(int int1){
       System.out.println(int1 + " in binary is");
       System.out.println(Integer.toBinaryString(int1));
   }
}

这篇关于Java中十进制转二进制的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！