在 GCC 中编译而不生成输出文件 [英] Compile without generating output file in GCC

问题描述

$ gcc -c somefile.c 编译不链接，生成对应的somefile.o.

$ gcc -c somefile.c compiles without linking and generates the corresponding somefile.o.

是否可以在 gcc 中编译文件而不生成任何输出文件?

Is it possible to compile files in gcc without generating any output file?

我知道还有其他方法可以实现这一点，但我很好奇是否有一个标志仅用于遍历源代码以查找错误/警告.

I know there are other ways to achieve this but I'm curious on whether there is a flag just for going through the source code looking for errors/warnings.

推荐答案

您可能喜欢 -fsyntax-only 选项.它不会在磁盘上写入任何内容，只是检查代码是否有效.

You may like the -fsyntax-only option. It does not write anything on disk, just checks that the code is valid.

您可以使用以下命令检查它是否没有在磁盘上写入任何内容:

You can check that it does not write anything on disk with this command:

$ strace -e write -f gcc -fsyntax-only test.c
Process 14033 attached
[pid 14033] +++ exited with 0 +++
--- SIGCHLD {si_signo=SIGCHLD, si_code=CLD_EXITED, si_pid=14033, si_status=0, si_utime=0, si_stime=0} ---
+++ exited with 0 +++

与使用 -c -o/dev/null 的其他命令进行比较:

Compare with this other command that uses -c -o /dev/null instead:

rodrigo@P41CCTX5:/tmp$ strace -e write -f gcc -c -o /dev/null test.c
Process 14182 attached
[pid 14182] write(3, "	.file	"a.c"
	.text
	.globl	foo
"..., 353) = 353
[pid 14182] +++ exited with 0 +++
--- SIGCHLD {si_signo=SIGCHLD, si_code=CLD_EXITED, si_pid=14182, si_status=0, si_utime=0, si_stime=1} ---
Process 14183 attached
[pid 14183] write(3, "a.cfoo", 9) = 9
[pid 14183] write(3, "U211345]303GCC: (Ubuntu 4.8.2-19ubunt"..., 42) = 42
[pid 14183] write(3, "241zR1|10133f4421013434"..., 56) = 56
....
[pid 14183] +++ exited with 0 +++
--- SIGCHLD {si_signo=SIGCHLD, si_code=CLD_EXITED, si_pid=14183, si_status=0, si_utime=0, si_stime=0} ---
+++ exited with 0 +++

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