从行具有最大日期的表中选择信息 [英] Select info from table where row has max date
问题描述
我的桌子看起来像这样:
My table looks something like this:
group date cash checks
1 1/1/2013 0 0
2 1/1/2013 0 800
1 1/3/2013 0 700
3 1/1/2013 0 600
1 1/2/2013 0 400
3 1/5/2013 0 200
-- 不需要现金只是证明表中有更多信息
-- Do not need cash just demonstrating that table has more information in it
我想获取日期为最大值且支票大于 0 的每个唯一组.因此返回将类似于:
I want to get the each unique group where date is max and checks is greater than 0. So the return would look something like:
group date checks
2 1/1/2013 800
1 1/3/2013 700
3 1/5/2013 200
尝试的代码:
SELECT group,MAX(date),checks
FROM table
WHERE checks>0
GROUP BY group
ORDER BY group DESC
问题是它给了我所有的日期和支票,而不仅仅是最大日期行.
problem with that though is it gives me all the dates and checks rather than just the max date row.
使用 ms sql server 2005
using ms sql server 2005
推荐答案
SELECT group,MAX(date) as max_date
FROM table
WHERE checks>0
GROUP BY group
这可以获取最大日期..将其加入您的数据以获取其他列:
That works to get the max date..join it back to your data to get the other columns:
Select group,max_date,checks
from table t
inner join
(SELECT group,MAX(date) as max_date
FROM table
WHERE checks>0
GROUP BY group)a
on a.group = t.group and a.max_date = date
内连接用作过滤器,仅获取最大记录.
Inner join functions as the filter to get the max record only.
仅供参考,您的列名很糟糕,不要对列(组、日期、表)使用保留字.
FYI, your column names are horrid, don't use reserved words for columns (group, date, table).
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