为什么在块外设置时`scheduledTimer` 会正确触发,而不是在块内设置? [英] Why would a `scheduledTimer` fire properly when setup outside a block, but not within a block?
问题描述
以下代码片段在完成块外部调用时可以完美运行,但是当我在块内部设置它时,计时器永远不会被触发.我不明白为什么会有区别:
The following code snippet works perfectly when called outside a completion block, but the timer is never fired when I set it up inside the block. I don't understand why there is a difference:
self.timer = Timer.scheduledTimer(timeInterval: 1,
target: self,
selector: #selector(self.foo),
userInfo: nil,
repeats: true)
最初在块外调用它时,我没有使用自引用,但是一旦在块内调用它,就需要它.但是我再次在块外测试了完全相同的代码,它仍然有效.
I was not using the self references when calling it initially outside the block, but then once inside, it was required. However I tested the exact same code outside the block again and it does still work.
块是一个完成处理程序,在请求HealthKit
相关信息的许可后调用.
The block is a completion hander that is called after asking permission for HealthKit
related information.
推荐答案
问题是有问题的完成块可能没有在主线程上运行,因此没有运行循环.但是计时器需要在运行循环中进行调度,而主线程有一个,但大多数后台线程没有(除非您自己添加一个).
The issue is that the completion block in question was probably not running on the main thread and therefore didn't have a run loop. But timers need to be scheduled on a run loop, and while the main thread has one, most background threads do not (unless you add one, yourself).
为了解决这个问题,在那个完成处理程序中,将计时器的创建分派回主线程,它应该可以正常工作:
To fix this, in that completion handler, dispatch the creation of the timer back to the main thread and it should work fine:
DispatchQueue.main.async {
self.timer = Timer.scheduledTimer(timeInterval: 1.0, target: self, selector: #selector(handleTimer(_:)), userInfo: nil, repeats: true)
}
或者使用调度源计时器(可以为后台队列调度的计时器,并且不需要运行循环).
Or use a dispatch source timer (a timer that can be scheduled for a background queue, and doesn't require a run loop).
var timer: DispatchSourceTimer!
private func startTimer() {
let queue = DispatchQueue(label: "com.domain.app.timer")
timer = DispatchSource.makeTimerSource(queue: queue)
timer.setEventHandler { [weak self] in
// do something
}
timer.schedule(deadline: .now(), repeating: 1.0)
timer.resume()
}
有关早期 Swift 版本的语法,请参阅此答案的先前修订版.
For syntax for earlier version of Swift, see previous revision of this answer.
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