使用 Swift 3 获取 iPhone 或 iPad 设备的 IP 地址 [英] Get IPAddress of iPhone or iPad device Using Swift 3

问题描述

如何使用 Swift 3 编程语言在不使用任何第三方库的情况下检索设备的 IP 地址?我使用以下代码来获取 IP 地址:

How to retrieve the device's IP address without using any third-party libraries using Swift 3 programming language? I have used the following code in order to get the IP address:

func getIPAddress() -> String? {
    var address : String?

    var ifaddr : UnsafeMutablePointer<ifaddrs> = nil
    if getifaddrs(&ifaddr) == 0 {

        var ptr = ifaddr
        while ptr != nil {
            defer { ptr = ptr.memory.ifa_next }

            let interface = ptr.memory

            let addrFamily = interface.ifa_addr.memory.sa_family
            if addrFamily == UInt8(AF_INET) || addrFamily == UInt8(AF_INET6) {

                if let name = String.fromCString(interface.ifa_name) where name == "en0" {

                    var hostname = [CChar](count: Int(NI_MAXHOST), repeatedValue: 0)
                    getnameinfo(interface.ifa_addr, socklen_t(interface.ifa_addr.memory.sa_len),
                                &hostname, socklen_t(hostname.count),
                                nil, socklen_t(0), NI_NUMERICHOST)
                    address = String.fromCString(hostname)
                }
            }
        }

        freeifaddrs(ifaddr)
    }

    return address
 }

但是 UnsafeMutablePointer 语法不起作用.它会引发语法错误.我需要导入一个框架来帮助我吗?

But the UnsafeMutablePointer<ifaddrs> syntax is not working. It throws a syntax error. Do I need to import a framework to try to help me?

推荐答案

在您的桥接头中添加 #include.

这是获取IP地址所需的框架.

This is the framework needed to get IP address.

您也可以参考以下链接:

Also you can refer the following link:

Swift - 获取设备的 IP 地址

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