如何在 Django 模型表单中显示用户的 get_full_name() 而不是用户名? [英] How to display a user's get_full_name() instead of the username in a Django model form?
问题描述
我有一个引用 ForeignKey(User)
字段的模型.
I have a model that references a ForeignKey(User)
field.
当用户在他的表单上选择一个项目时,我希望他们能够看到 get_full_name()
而不仅仅是 username
.
When a user selects an item on his form I would like them to be able to see the get_full_name()
instead of just the username
.
class Books(models.Model):
author = models.ForeignKey(User)
推荐答案
这可以通过多种方式完成.
This can be done several ways.
创建一个 User
的代理子类并覆盖它的 __unicode__()
方法以返回用户的全名.
Create a proxy subclass of User
and override its __unicode__()
method to return user's full name.
class UserFullName(User):
class Meta:
proxy = True
def __unicode__(self):
return self.get_full_name()
现在在您的模型表单中,使用 UserFullName
来检索用户.
Now in your model form, use UserFullName
to retrieve users.
class BookForm(forms.ModelForm):
author = forms.ModelChoiceField(queryset=UserFullName.objects.all())
class Meta:
model = Book
<小时>
另一种方法是在表单的构造函数中动态填充选项.
Another way is to dynamically populate choices in form's constructor.
class BookForm(forms.ModelForm):
def __init__(self, *args, **kwargs):
super(BookForm, self).__init__(*args, **kwargs)
users = User.objects.all()
self.fields['author'].choices = [(user.pk, user.get_full_name()) for user in users]
class Meta:
model = Book
<小时>
也许,lazerscience 展示了最djangonic"的方式作为对类似问题的回答 Django 表单:如何动态创建 ModelChoiceField 标签.它继承了 ModelChoiceField
并覆盖了其用于提供选择标签的 label_from_instance()
方法.
Perhaps, the most "djangonic" way is demonstrated by lazerscience as an answer to the similar question Django forms: how to dynamically create ModelChoiceField labels. It subclasses ModelChoiceField
and overrides its label_from_instance()
method that is intended to provide choice labels.
class UserFullnameChoiceField(forms.ModelChoiceField):
def label_from_instance(self, obj):
return smart_unicode(obj.get_full_name())
class BookForm(forms.ModelForm):
author = UserFullnameChoiceField(queryset=User.objects.all())
class Meta:
model = Book
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