在 Java 中执行 javascript - 打开 URL 并获取链接 [英] Executing javascript in java - Opening a URL and getting links

问题描述

import javax.script.ScriptEngine;
import javax.script.ScriptEngineManager;
import java.io.FileReader;

public class Main {

    public static void main(String[] args) {

        ScriptEngineManager manager = new ScriptEngineManager();
        ScriptEngine engine = manager.getEngineByName("js");
        try {
            FileReader reader = new FileReader("C:/yourfile.js");
            engine.put("urlfromjava", "http://www.something.com/?asvb");
            engine.eval(reader);
            reader.close();
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

现在，yourfile.js 包含这一行

Right now, the yourfile.js contains this line

function urlget(url)
{
    print("URL:"+url);
    var loc = window.open(url);
    var link = document.getElementsByTagName('a')["61"].href;
    return ("
Link is: 
"+link); 

}
var x = urlget(urlfromjava);
print(x);

我收到错误

"javax.script.ScriptException: sun.org.mozilla.javascript.internal.EcmaError: ReferenceError: "window" is not defined"

如何打开一个 URL 并从 Java 中获取它的链接?

How to open a URL and get the links of it from java?

推荐答案

根据文档:

window 对象代表浏览器中打开的窗口.

The window object represents an open window in a browser.

由于您不是在浏览器中执行脚本，因此未定义窗口对象.

Since you are not executing your script in a browser, the window object is not defined.

您可以使用 URL/URLConnecion 类读取 URL 并将其提供给 ScriptEngine.这里有教程.

You can read the URL using the URL/URLConnecion classes and feed it to the ScriptEngine. There is a tutorial here.

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