转储包含来自 g++ 的路径 [英] Dump include paths from g++

问题描述

我正在尝试编写一个小构建脚本，并想确定包含是否为系统包含.所以我希望 g++ 告诉我它正在使用的包含路径.

I'm trying to write a little build script, and want to determine if the includes are system includes or not. So I want g++ to tell me the include path's it's using.

cpp -v 显然是最好的选择，但它没有给我 C++ 路径.

cpp -v seems the obvious best shot, but it doesn't give me the C++ paths.

所以我尝试了:

g++ -Xpreprocessor -v  

这不太正确 - g++ 捕获 -v 以作为它自己的详细输出.

Which doesn't work quite right - g++ captures the -v for it's own verbose output.

推荐答案

来自 Jonathan Wakely 的一个更好的选择(也适用于 clang):

From Jonathan Wakely a better option (works on clang too):

g++ -E -x c++ - -v < /dev/null 
clang++ -E -x c++ - -v < /dev/null

我注意到 cpp 中有一个用于指定语言的标志.这就像一个魅力.

I noticed there's a flag in cpp for specifying language. This works like a charm.

cpp -xc++ -v < /dev/null


#include "..." search starts here:
#include <...> search starts here:
 /usr/local/Cellar/gcc/4.7.0/gcc/lib/gcc/x86_64-apple-darwin11.4.0/4.7.0/../../../../include/c++/4.7.0
 /usr/local/Cellar/gcc/4.7.0/gcc/lib/gcc/x86_64-apple-darwin11.4.0/4.7.0/../../../../include/c++/4.7.0/x86_64-apple-darwin11.4.0
 /usr/local/Cellar/gcc/4.7.0/gcc/lib/gcc/x86_64-apple-darwin11.4.0/4.7.0/../../../../include/c++/4.7.0/backward
 /usr/local/Cellar/gcc/4.7.0/gcc/lib/gcc/x86_64-apple-darwin11.4.0/4.7.0/include
 /usr/local/include
 /usr/local/Cellar/gcc/4.7.0/gcc/include
 /usr/local/Cellar/gcc/4.7.0/gcc/lib/gcc/x86_64-apple-darwin11.4.0/4.7.0/include-fixed
 /usr/include
 /System/Library/Frameworks
 /Library/Frameworks
End of search list.

刚刚注意到在 gcc 4.2 上 -x c++ 是 -xc++ 很重要

Just noticed that it is important for the -x c++ to be -xc++ on gcc 4.2

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