列出 Python 类中的 @property 装饰方法 [英] list @property decorated methods in a python class

问题描述

是否可以获得类中所有 @property 修饰方法的列表?如果是这样怎么办?

示例:

class MyClass(object):@财产def foo(self):经过@财产定义栏(自我):经过

我如何从这个类中获取['foo', 'bar']?

解决方案

任何用 property 修饰的东西都会在你的类命名空间中留下一个专用对象.查看类的__dict__，或者使用vars()函数获取相同的，以及任何作为属性 类型匹配:

[name for name, value in vars(MyClass).items() if isinstance(value, property)]

演示:

<预><代码>>>>类我的类(对象):... @财产... def foo(self):... 经过... @财产...定义栏(自我):... 经过...>>>变量(我的类)dict_proxy({'__module__': '__main__', 'bar': <property object at 0x1006620a8>, '__dict__': <attribute '__dict__' of 'MyClass' objects>, 'foo': <property object at 0x1006620a8>;, '__weakref__': <'MyClass' 对象的属性 '__weakref__', '__doc__': None})>>>[名称的名称，vars(MyClass).items() 中的值如果 isinstance(value, property)]['bar', 'foo']

请注意，这将包括任何直接使用 property() 的内容(这就是装饰器所做的，真的)，并且名称的顺序是任意的(因为字典没有固定顺序).

Is it possible to obtain a list of all @property decorated methods in a class? If so how?

Example:

class MyClass(object):
    @property
    def foo(self):
        pass
    @property
    def bar(self):
        pass

How would I obtain ['foo', 'bar'] from this class?

解决方案

Anything decorated with property leaves a dedicated object in your class namespace. Look at the __dict__ of the class, or use the vars() function to obtain the same, and any value that is an instance of the property type is a match:

[name for name, value in vars(MyClass).items() if isinstance(value, property)]

Demo:

>>> class MyClass(object):
...     @property
...     def foo(self):
...         pass
...     @property
...     def bar(self):
...         pass
... 
>>> vars(MyClass)
dict_proxy({'__module__': '__main__', 'bar': <property object at 0x1006620a8>, '__dict__': <attribute '__dict__' of 'MyClass' objects>, 'foo': <property object at 0x100662050>, '__weakref__': <attribute '__weakref__' of 'MyClass' objects>, '__doc__': None})
>>> [name for name, value in vars(MyClass).items() if isinstance(value, property)]
['bar', 'foo']

Note that this will include anything that used property() directly (which is what a decorator does, really), and that the order of the names is arbitrary (as dictionaries have no set order).

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