如何将函数作为参数传递给elisp? [英] How do I pass a function as a parameter to in elisp?

问题描述

我试图在 elisp 中将一种方法传递给另一种方法，然后让那个方法执行它.下面是一个例子:

I'm trying to pass one method to another in elisp, and then have that method execute it. Here is an example:

(defun t1 ()
  "t1")

(defun t2 ()
  "t1")

(defun call-t (t)
  ; how do I execute "t"?
  (t))

; How do I pass in method reference?
(call-t 't1)

推荐答案

首先，我不确定将函数命名为 t 是否有帮助，因为 't' 用作 真值 lisp.

First, I'm not sure that naming your function t is helping as 't' is used as the truth value in lisp.

也就是说，以下代码对我有用:

That said, the following code works for me:

(defun test-func-1 ()  "test-func-1"
   (interactive "*")
   (insert-string "testing callers"))

(defun func-caller (callee)
  "Execute callee"
  (funcall callee))

(func-caller 'test-func-1)

请注意funcall"的使用，它会触发实际的函数调用.

Please note the use of 'funcall', which triggers the actual function call.

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